Math Problem Statement

Find an angle θ with 0° < θ < 360° that has the same sine and cosine as 50°.

Solution

Let's solve the problem step by step:

  1. Find an angle with the same sine as 5050^\circ:

    • The sine function is positive in the first and second quadrants.
    • The angle in the second quadrant that has the same sine as 5050^\circ is given by: θ=18050=130\theta = 180^\circ - 50^\circ = 130^\circ So, θ=130\theta = 130^\circ.
  2. Find an angle with the same cosine as 5050^\circ:

    • The cosine function is positive in the first and fourth quadrants.
    • The angle in the fourth quadrant that has the same cosine as 5050^\circ is given by: θ=36050=310\theta = 360^\circ - 50^\circ = 310^\circ So, θ=310\theta = 310^\circ.

Final Answers:

  • For the same sine as 5050^\circ: θ=130\theta = 130^\circ.
  • For the same cosine as 5050^\circ: θ=310\theta = 310^\circ.

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Related Questions:

  1. What are the general solutions for angles with the same sine or cosine in a full rotation?
  2. How does the unit circle help in determining angles with the same sine or cosine?
  3. What are the properties of sine and cosine functions in each quadrant?
  4. How are sine and cosine related to complementary angles?
  5. Can we determine these angles using radians instead of degrees?

Tip: Always remember the reference angle rules in trigonometry for determining equivalent angles in different quadrants!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Reference Angles
Sine and Cosine Properties

Formulas

Reference angle: θ = 180° - α (for sine in Quadrant II)
Reference angle: θ = 360° - α (for cosine in Quadrant IV)

Theorems

Properties of Sine: Sin(180° - θ) = Sin(θ)
Properties of Cosine: Cos(360° - θ) = Cos(θ)

Suitable Grade Level

Grades 9-12