The problem asks for the angle that is opposite (or "bertolak belakang") to ∠TOQ based on the provided diagram.

Analysis:

• The diagram shows several lines intersecting at point $O$.
• The angle ∠TOQ is indicated between the lines $TQ$ and $OQ$, and is labeled as $x^\circ$.
• There is another angle near point $O$ labeled as $2x^\circ$.
• Since the two angles form a straight line (linear pair), they must sum to $180^\circ$.

Step-by-step solution:

1. Since $\angle TOQ = x^\circ$ and $\angle SOQ = 2x^\circ$ form a linear pair: $x + 2x = 180^\circ$ Solving this gives: $3x = 180^\circ \quad \Rightarrow \quad x = 60^\circ$
2. The problem asks for the angle opposite (bertolak belakang) to ∠TOQ. Since ∠TOQ is $60^\circ$, its opposite angle (which is vertically opposite) is also $60^\circ$.

Thus, the correct answer is: $\boxed{60^\circ}$

Would you like further clarification or more details?

Related questions:

1. What is a linear pair of angles and how do they relate to straight angles?
2. How do vertically opposite angles work in intersecting lines?
3. How can we calculate unknown angles in geometric diagrams using algebra?
4. Can you explain the difference between complementary and supplementary angles?
5. How would the diagram change if the angle $2x$ were instead $3x$?

Tip: Vertically opposite angles are always equal when two lines intersect.