Math Problem Statement

the angle between x+y=0 and x-y=0 is

Solution

To find the angle between two lines, we use the formula:

tanθ=m1m21+m1m2\tan \theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right|

where m1m_1 and m2m_2 are the slopes of the two lines.

Step 1: Find the slopes of the given lines.

The equation of the first line is x+y=0x + y = 0. Rearranging into slope-intercept form (y=mx+by = mx + b):

y=xm1=1y = -x \quad \Rightarrow \quad m_1 = -1

The equation of the second line is xy=0x - y = 0. Rearranging it similarly:

y=xm2=1y = x \quad \Rightarrow \quad m_2 = 1

Step 2: Use the formula for the angle.

Now, substitute m1=1m_1 = -1 and m2=1m_2 = 1 into the angle formula:

tanθ=111+(1)(1)\tan \theta = \left| \frac{-1 - 1}{1 + (-1)(1)} \right|

Simplifying:

tanθ=211=20\tan \theta = \left| \frac{-2}{1 - 1} \right| = \left| \frac{-2}{0} \right|

Since division by zero is undefined, this means the two lines are perpendicular.

Conclusion:

The angle between the two lines is 9090^\circ.

Let me know if you'd like any further clarification or details!


Here are some follow-up questions to explore:

  1. How do you find the angle between two non-perpendicular lines?
  2. What does it mean geometrically for two lines to be perpendicular?
  3. How would you calculate the angle between two lines in three-dimensional space?
  4. How can you determine if two lines are parallel from their equations?
  5. What are the steps to finding the angle between two curves?

Tip: When the denominator of the tangent formula is zero, the lines are perpendicular.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Slope of a Line
Angle Between Two Lines

Formulas

tan(θ) = |(m1 - m2) / (1 + m1 * m2)|

Theorems

Perpendicular Lines Theorem

Suitable Grade Level

Grades 9-11