Math Problem Statement

solve this cs honour question

Two logic gates are the AND gate and the OR gate. Complete the truth tables for these two gates:

Solution

The question is asking to complete the truth tables for the AND gate and the OR gate based on the given input combinations for AA and BB.

AND Gate Truth Table:

The AND gate outputs a value of 1 only when both inputs AA and BB are 1. Otherwise, it outputs 0.

\hline A & B & X (\text{A AND B}) \\ \hline 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \\ \hline \end{array}$$ ### OR Gate Truth Table: The OR gate outputs a value of **1** when at least one input $$A$$ or $$B$$ is **1**. It only outputs **0** when both inputs are **0**. $$\begin{array}{|c|c|c|} \hline A & B & X (\text{A OR B}) \\ \hline 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline \end{array}$$ ### Completed Answer: - The AND gate truth table: $$X = A \land B$$ - The OR gate truth table: $$X = A \lor B$$ Let me know if you need further clarification or details! --- Here are 5 questions to expand your understanding: 1. What is the difference between the AND and OR gates in terms of logical operations? 2. How would you represent an XOR (exclusive OR) gate in a truth table? 3. Can you explain a real-life example where an AND gate might be used? 4. What would the truth table look like for a NAND gate (NOT AND)? 5. How does Boolean algebra simplify logic circuits using these gates? **Tip**: When working with more complex circuits, combining multiple gates can achieve specific behaviors, and simplifying them through Boolean algebra is often key to designing efficient systems.

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Math Problem Analysis

Mathematical Concepts

Logic Gates
Truth Tables
Boolean Algebra

Formulas

AND Gate: X = A AND B
OR Gate: X = A OR B

Theorems

Boolean Theorem for AND Gate: Outputs 1 when both inputs are 1
Boolean Theorem for OR Gate: Outputs 1 when at least one input is 1

Suitable Grade Level

Grades 9-12