Math Problem Statement

Part 1 of 2

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Part 1

Amaya is standing 30 ft from a volleyball net. The net is 8 ft high. Amaya serves the ball. The path of the ball is modeled by the equation

y equals negative 0.02 left parenthesis x minus 18 right parenthesis squared plus 12y=−0.02(x−18)2+12​,

where x is the​ ball's horizontal distance in feet from​ Amaya's position and y is the distance in feet from the ground to the ball.

a. How far away is the ball from Amaya when it is at its maximum​ height? Explain.

b. Describe how you would find the​ ball's height when it crosses the net at

xequals=30.

Question content area bottom

Part 1

a. How far away is the ball from Amaya when it is at its maximum​ height? Explain.

The ball is

enter your response here

ft away from Amaya when it is at its maximum height. Use the

▼   x-coordinate

y-coordinate

of the vertex.

The ball isft away from Amaya when it is at its maximum height.Use theof the vertex.

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Math Problem Analysis

Mathematical Concepts

Quadratic Equations
Vertex of a Parabola

Formulas

Quadratic equation form: y = ax^2 + bx + c
Vertex form: y = a(x - h)^2 + k

Theorems

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Suitable Grade Level

High School