Math Problem Statement
Определить тип особой точки z = 0 для данной функции
Solution
To determine the type of singularity at for the given function
we analyze the behavior of the function around :
Step-by-step Analysis:
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Expand in a Taylor series around : Therefore:
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Simplify the numerator of : The numerator of becomes:
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Expand : Recall the series expansion of : Substituting :
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Behavior of near : Combining the two terms, the function becomes: Multiply the terms:
- The leading term in the product is:
- Higher-order terms are of the form etc.
Hence, near , , meaning is a removable singularity because the function is analytic there after division by .
Conclusion:
The singularity at for the given function is a removable singularity.
Would you like further clarification or additional examples?
Related Questions:
- What are the different types of singularities in complex analysis?
- How can Taylor expansions help analyze singularities?
- How does the behavior of near affect singularities?
- Could this function have other singularities besides ?
- How do Laurent series differ from Taylor series in classifying singularities?
Tip:
When analyzing singularities, always focus on the leading-order term of the Laurent series to determine the type of singularity.
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Math Problem Analysis
Mathematical Concepts
Complex Analysis
Singularities
Taylor Series
Laurent Series
Formulas
e^x = 1 + x + x^2/2! + x^3/3! + ...
cot(x) = 1/x - x/3 - x^3/45 + ...
Laurent series expansion to analyze singularities
Theorems
Definition of removable singularities
Taylor series expansion theorem
Properties of cotangent function near zero
Suitable Grade Level
Undergraduate Mathematics
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