Math Problem Statement
Answer the questions about the following polynomial.
minus, start fraction, x, to the power 4 , divided by, 5, end fraction, minus, 1
−5x4−1
Answer
Attempt 1 out of 2
The expression represents a linearcubicquadraticquinticquartic polynomial with terms. The constant term is , the leading term is , and the leading coefficient is .
Solution
Let's analyze the given polynomial expression:
Analyzing the Polynomial
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Degree of the Polynomial: The degree of a polynomial is the highest power of the variable in the expression. In this case, the highest power of is 4 (from the term ). Therefore, the polynomial is of degree 4. This means it is a quartic polynomial.
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Number of Terms: A polynomial is made up of terms separated by addition or subtraction. The given polynomial has two terms:
So, there are 2 terms.
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Constant Term: The constant term in a polynomial is the term without any variable (without ). In this polynomial, the constant term is .
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Leading Term: The leading term of a polynomial is the term with the highest degree. Here, the leading term is .
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Leading Coefficient: The leading coefficient is the coefficient of the leading term. The leading term is , so the leading coefficient is .
Filling in the Blanks
Based on the analysis above:
- The expression represents a quartic polynomial with 2 terms.
- The constant term is .
- The leading term is .
- The leading coefficient is .
Would you like more details or have any other questions?
Related Questions to Expand Understanding:
- How do you classify polynomials based on their degree?
- What is the difference between a quartic and a cubic polynomial?
- How do you determine the leading coefficient in a polynomial?
- What are some common methods to solve quartic polynomials?
- How does the sign of the leading coefficient affect the graph of a polynomial?
Tip: When dealing with fractions in polynomials, always identify the coefficient separately from the variable and its exponent for clarity.
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Math Problem Analysis
Mathematical Concepts
Polynomials
Formulas
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Theorems
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Suitable Grade Level
High School
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