Math Problem Statement

U=ℤ

P(x,y,z) : x+y-z=xy

∀z∃yp(5,y,z)

Solution

Let's analyze the logical statement given the new set U=ZU = \mathbb{Z} (the set of integers) and the predicate P(x,y,z)P(x, y, z) defined as:

P(x,y,z):x+yz=xyP(x, y, z) : x + y - z = xy

The problem asks us to determine whether the following statement is true:

zyP(5,y,z)\forall z \, \exists y \, P(5, y, z)

In other words, we need to check whether, for every integer zz, there exists an integer yy such that the equation 5+yz=5y5 + y - z = 5y holds true.

Step 1: Simplify the equation

Starting with the equation:

5+yz=5y5 + y - z = 5y

We can rearrange this to solve for yy:

5z=5yy5 - z = 5y - y

5z=4y5 - z = 4y

y=5z4y = \frac{5 - z}{4}

Step 2: Analyze the solution

For yy to be an integer, the expression 5z4\frac{5 - z}{4} must also be an integer. This means that 5z5 - z must be divisible by 4.

So, the condition becomes:

5z0(mod4)5 - z \equiv 0 \pmod{4}

This can be rewritten as:

z1(mod4)z \equiv 1 \pmod{4}

Step 3: Determine the truth of the statement

Given the condition z1(mod4)z \equiv 1 \pmod{4}, this equation only holds when zz is congruent to 1 modulo 4. Therefore, yy exists and is an integer for such values of zz.

However, the original statement zyP(5,y,z)\forall z \, \exists y \, P(5, y, z) requires that for every integer zz, there exists a corresponding integer yy that satisfies the equation. This is not true because there are values of zz that do not satisfy z1(mod4)z \equiv 1 \pmod{4}, which would make yy non-integral.

Conclusion

The statement:

zyP(5,y,z)\forall z \, \exists y \, P(5, y, z)

is false because there are integers zz for which no integer yy can satisfy the equation 5+yz=5y5 + y - z = 5y.

Do you have any questions or would you like further details?

Here are some related questions you might consider:

  1. What specific values of zz fail to satisfy the equation, and why?
  2. How would the solution change if xx were a different integer?
  3. What if the equation were slightly modified, e.g., x+yz=xy+1x + y - z = xy + 1?
  4. How can you determine for which integers zz the equation has an integer solution for yy?
  5. Can you generalize this result to other similar equations involving integers?

Tip: When solving equations over integers, check if the solution requires divisibility by a certain number—this can restrict the values of variables and impact the truth of logical statements.

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Math Problem Analysis

Mathematical Concepts

Predicate logic
Modular arithmetic

Formulas

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Theorems

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Suitable Grade Level

Advanced