Math Problem Statement

x^2=(Y-2) fin vertex, directrix, axis of symmetry, an focus

Solution

The equation x2=y2x^2 = y - 2 describes a parabola. To analyze its properties like the vertex, directrix, axis of symmetry, and focus, we should first rewrite the equation in a standard form.

Step 1: Rewrite in Standard Form

The standard form of a parabola that opens either upwards or downwards is:

(xh)2=4p(yk)(x - h)^2 = 4p(y - k)

where (h,k)(h, k) is the vertex of the parabola, and pp is the distance from the vertex to the focus or directrix.

Given equation: x2=y2x^2 = y - 2

This can be rewritten as: x2=1(y2)x^2 = 1 \cdot (y - 2)

Here, we can compare it with the standard form (xh)2=4p(yk)(x - h)^2 = 4p(y - k):

  • h=0h = 0
  • k=2k = 2
  • 4p=14p = 1 (so p=14p = \frac{1}{4})

Step 2: Identify the Vertex

The vertex of the parabola is given by (h,k)(h, k), which is:

Vertex=(0,2)\text{Vertex} = (0, 2)

Step 3: Find the Focus

The focus lies at a distance pp from the vertex along the axis of symmetry. Since p=14p = \frac{1}{4} and the parabola opens upwards (as x2x^2 is positive):

Focus=(0,2+14)=(0,94)\text{Focus} = \left(0, 2 + \frac{1}{4}\right) = \left(0, \frac{9}{4}\right)

Step 4: Find the Directrix

The directrix is a line that is pp units away from the vertex, but in the opposite direction (downwards in this case):

Directrix=y=214=74\text{Directrix} = y = 2 - \frac{1}{4} = \frac{7}{4}

Step 5: Find the Axis of Symmetry

The axis of symmetry is the vertical line that passes through the vertex:

Axis of Symmetry=x=0\text{Axis of Symmetry} = x = 0

Summary of Properties:

  • Vertex: (0,2)(0, 2)
  • Focus: (0,94)\left(0, \frac{9}{4}\right)
  • Directrix: y=74y = \frac{7}{4}
  • Axis of Symmetry: x=0x = 0

Would you like more details or have any other questions?

Related Questions:

  1. How would these properties change if the parabola opened sideways?
  2. Can you derive the equation for a parabola with a given focus and directrix?
  3. What would be the length of the latus rectum of this parabola?
  4. How does the graph of this parabola look compared to y=x2y = x^2?
  5. How do changes in the coefficient of x2x^2 affect the focus and directrix?

Tip:

Remember that the sign and coefficient in front of x2x^2 or y2y^2 in a parabola's equation determine the direction in which it opens and how "wide" or "narrow" it is.

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Math Problem Analysis

Mathematical Concepts

Parabolas
Vertex form of a parabola
Focus and directrix of a parabola

Formulas

Standard form of a parabola: (x - h)^2 = 4p(y - k)

Theorems

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Suitable Grade Level

High School