Math Problem Statement
Solution
Looking at the graph provided and the given options, let's analyze the statements one by one:
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Statement A: "f is continuous at "
- From the graph, we can see that there is a discontinuity at because there is a hole (open circle) at that point. The function does not take a value at , so this statement is false.
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Statement B: "f has a relative maximum at "
- The function seems to reach a peak at , indicating a relative maximum. Thus, this statement is true.
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Statement C: "x = a is in the domain of f"
- Since the graph has a hole at , it means the function is not defined at this point. So, this statement is false.
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Statement D: "The right-hand limit and left-hand limit of as approaches are equal"
- Both the left-hand and right-hand limits appear to approach the same value as approaches , even though the function is not defined at . Hence, this statement is true.
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Statement E: "The limit of as approaches exists"
- Since both the left-hand and right-hand limits exist and are equal, the limit exists. Thus, this statement is true.
Conclusion:
The false statement is A. The function is not continuous at .
Do you want more details or have any further questions? Here are some related questions:
- What is the formal definition of continuity at a point?
- How do we calculate left-hand and right-hand limits?
- What are the necessary conditions for a relative maximum or minimum?
- Why is it important that limits from both sides agree for the limit to exist?
- How do discontinuities affect the behavior of a function?
Tip: Always check for open and closed circles in graphs—they indicate whether a function is defined at that point.
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Math Problem Analysis
Mathematical Concepts
Limits
Continuity
Domain
Relative Maximum
Formulas
Limit: lim(x→a) f(x)
Right-hand and Left-hand limits
Theorems
Continuity at a point
Limit existence theorem
Suitable Grade Level
Grades 11-12 (Pre-Calculus or Calculus)