Math Problem Statement

f(x)=x24x+5=\sqrt{x^2-4x+5}

Solution

The given function is:

f(x)=x24x+5f(x) = \sqrt{x^2 - 4x + 5}

To understand the behavior and analyze this function, it is helpful to simplify the expression under the square root. Let's rewrite the quadratic expression inside the square root in a more convenient form by completing the square.

Step 1: Completing the square

The quadratic expression is x24x+5x^2 - 4x + 5. To complete the square, we focus on the first two terms x24xx^2 - 4x.

  1. Take half of the coefficient of xx, which is 4-4, and divide it by 2 to get 2-2.
  2. Square 2-2 to get 44.

Now, rewrite x24xx^2 - 4x as:

x24x=(x2)24x^2 - 4x = (x - 2)^2 - 4

Thus, the original quadratic expression becomes:

x24x+5=(x2)24+5=(x2)2+1x^2 - 4x + 5 = (x - 2)^2 - 4 + 5 = (x - 2)^2 + 1

Step 2: Substituting back into the original function

Now, we substitute this back into the original function:

f(x)=(x2)2+1f(x) = \sqrt{(x - 2)^2 + 1}

Step 3: Interpretation

The expression f(x)=(x2)2+1f(x) = \sqrt{(x - 2)^2 + 1} shows that the function represents the distance from any point xx on the real line to the point x=2x = 2 along the x-axis, but shifted vertically by 1. The minimum value of the expression inside the square root is 11, which occurs when x=2x = 2. Therefore, the minimum value of f(x)f(x) is:

f(2)=(22)2+1=1=1f(2) = \sqrt{(2 - 2)^2 + 1} = \sqrt{1} = 1

Step 4: Domain of the function

Since the expression inside the square root, (x2)2+1(x - 2)^2 + 1, is always positive for all real xx, the function is defined for all real numbers. Thus, the domain of f(x)f(x) is:

Domain of f(x):R\text{Domain of } f(x): \mathbb{R}

Step 5: Range of the function

Since the minimum value of f(x)f(x) is 11 and there is no upper bound (because (x2)2(x - 2)^2 can grow infinitely large), the range of f(x)f(x) is:

Range of f(x):[1,)\text{Range of } f(x): [1, \infty)

Final Form of the Function:

The function can be written as:

f(x)=(x2)2+1f(x) = \sqrt{(x - 2)^2 + 1}

Questions for Further Exploration:

  1. How does the graph of f(x)f(x) look like?
  2. What are the asymptotes or key features of the graph of f(x)f(x)?
  3. How does the function behave as xx approaches infinity or negative infinity?
  4. How would the graph of f(x)f(x) change if the constant +1+1 inside the square root were replaced with another value?
  5. How does completing the square help in analyzing functions involving square roots?

Tip:

When analyzing functions involving square roots, always check for opportunities to complete the square, as it can simplify the expression and make it easier to identify the key properties of the function.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Completing the Square
Square Roots

Formulas

f(x) = sqrt(x^2 - 4x + 5)
Completing the Square
Domain of a square root function
Range of a square root function

Theorems

Completing the square theorem
Properties of square root functions

Suitable Grade Level

Grades 9-11