In the provided figure, two electromagnetic waves are depicted traveling through a vacuum. To determine the correct statement about their frequency and speed, let's analyze the following:

1. Frequency Comparison: Frequency is related to the wavelength, where a shorter wavelength indicates a higher frequency, and a longer wavelength indicates a lower frequency. From the image, wave $E_A$ has a shorter wavelength compared to wave $E_B$. Therefore, wave $E_A$ has a higher frequency than wave $E_B$.

2. Speed of Electromagnetic Waves in a Vacuum: In a vacuum, all electromagnetic waves travel at the same speed, which is the speed of light ($c \approx 3 \times 10^8 \, \text{m/s}$). Hence, regardless of their frequency, both waves travel at the same speed.

Correct Answer

Given these observations, the correct statement is:

• "The frequency of wave A is greater than that of wave B, but the speeds of the two waves are the same."

Let me know if you would like further details on this topic or have additional questions. Here are some follow-up questions to explore:

1. How is wavelength related to the energy of a wave?
2. What effect does changing the medium have on the speed of an electromagnetic wave?
3. Why do all electromagnetic waves travel at the same speed in a vacuum?
4. How does frequency relate to the energy carried by an electromagnetic wave?
5. What is the relationship between frequency and wavelength in the electromagnetic spectrum?

Tip: Remember that in a vacuum, the speed of all electromagnetic waves is constant regardless of their frequency or wavelength.