Math Problem Statement
It's wrong answer, the Cardinality of the set A is 12
Solution
Let's re-evaluate the problem step by step to identify any mistakes in the initial solution.
Given the function , let's carefully determine the domain of by addressing the constraints again.
Step 1: Analyze the Domain Constraints
Condition 1: Non-negativity of the square root argument
This inequality holds when:
So, must be in the intervals .
Condition 2: Denominator not equal to zero
Step 2: Combine the Conditions
From Condition 1, must be in . From Condition 2, .
Thus, the combined domain of is:
Step 3: Determine the Integers not in the Domain
We need to identify the set of integers that are not in the domain of .
The integers not in the domain are:
- All integers between and , inclusive.
- The integer is specifically excluded.
So, the set includes all integers from to inclusive, and also excludes .
List the integers from to :
Step 4: Find the Cardinality of the Set
The set contains the following integers:
Counting these integers, we have:
Re-check for Set Exclusion
- Since is explicitly mentioned, we don't include it in the interval.
Thus, the set consists of 11 elements, not 12.
Therefore, the correct cardinality of the set is .
Do you want further details or have any questions? Here are some related questions you might find interesting:
- How do you determine the domain of a function involving a square root and a fraction?
- What are the steps to solve inequalities involving quadratic expressions?
- How do you find the cardinality of a set?
- What are some examples of functions with restricted domains?
- How do you solve compound inequalities?
Tip: When dealing with functions, always carefully check the interval boundaries and excluded points to ensure the domain is correctly identified.
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Math Problem Analysis
Mathematical Concepts
Functions
Domain and Range
Inequalities
Formulas
Quadratic inequalities
Theorems
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Suitable Grade Level
Grades 10-12
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