Math Problem Statement

Based on the image, solve the mathematical problems regarding rational functions, horizontal asymptotes, and end behavior analysis.

Solution

The uploaded image contains mathematical problems. I'll provide solutions to the questions in the image. Let’s go through each problem one by one.


Problem 12

(i) Solve g(x)=3g(x) = 3:
The equation to solve is g(x)=3g(x) = 3, but we need more information about g(x)g(x) (e.g., its formula). Could you clarify or upload more of the question?

(ii) Determine the end behavior of g(x)g(x) as xx \to -\infty:
Similarly, the answer depends on the function g(x)g(x). Please provide its definition.


Problem 13

The rational function is f(x)=k(x1)(x+3)x2+2x5f(x) = \frac{k(x-1)(x+3)}{x^2 + 2x - 5}.

To determine when f(x)f(x) has a horizontal asymptote at y=0y = 0, recall the rule for horizontal asymptotes in rational functions:

  • If the degree of the numerator is less than the degree of the denominator, y=0y = 0 is a horizontal asymptote.
  • The degree of the numerator is determined by the term k(x1)(x+3)k(x-1)(x+3), which has degree 2.
  • The degree of the denominator x2+2x5x^2 + 2x - 5 is also 2.

Thus, for y=0y = 0 to be a horizontal asymptote, the numerator's leading coefficient must be smaller than the denominator's. This happens when k=2k = 2, because this balances the numerator's growth relative to the denominator.

Answer: k=2k = 2 (Option A).


Problem 14

The rational function is given as r(x)=(2x3)(x4)(x2)(3x1)(2x+1)(x1)r(x) = \frac{(2x-3)(x-4)(x-2)}{(3x-1)(2x+1)(x-1)}.
Let’s analyze the degree of r(x)r(x):

  • The numerator has degree 3 (since it’s the product of three linear terms).
  • The denominator also has degree 3 (since it’s the product of three linear terms).

Thus, the degrees of p(x)p(x) and q(x)q(x) are equal, and for large xx, the horizontal asymptote is determined by the ratio of leading coefficients:
limxr(x)=leading coefficient of numeratorleading coefficient of denominator=26=13.\lim_{x \to \infty} r(x) = \frac{\text{leading coefficient of numerator}}{\text{leading coefficient of denominator}} = \frac{2}{6} = \frac{1}{3}.

Answer: Option D.


Do you need more detailed steps for any of these? Here are related questions for further practice:

  1. For g(x)=2x3+3x2x+1g(x) = 2x^3 + 3x^2 - x + 1, find where g(x)=5g(x) = 5.
  2. For f(x)=k(x2)(x+5)x2+4x+4f(x) = \frac{k(x-2)(x+5)}{x^2 + 4x + 4}, determine the value of kk for y=0y = 0.
  3. Analyze the horizontal asymptote for r(x)=x2+3x+1x3+2x+1r(x) = \frac{x^2 + 3x + 1}{x^3 + 2x + 1}.
  4. What happens to f(x)=x3+2x24xf(x) = \frac{x^3 + 2}{x^2 - 4x} as x±x \to \pm \infty?
  5. How does the degree of the numerator and denominator affect the horizontal asymptotes?

Tip: Always check the degrees of the numerator and denominator to quickly determine horizontal asymptotes!

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Math Problem Analysis

Mathematical Concepts

Rational functions
Horizontal asymptotes
End behavior of functions
Limits

Formulas

Degree of numerator vs. denominator
Horizontal asymptote rules
lim_{x->∞} f(x)

Theorems

Limit of rational functions as x approaches infinity
Degree-based asymptote rules

Suitable Grade Level

Grades 10-12