Math Problem Statement

Let f(x)=2x2+7x-153x2-10x+3

This function has:

  1. y intercept at the point   

2) x intercepts at the point(s)   

  1. Vertical asymptotes at x =   

Solution

To analyze the function f(x)=2x2+7x153x210x+3f(x) = \frac{2x^2 + 7x - 15}{3x^2 - 10x + 3}, let’s determine the required properties step-by-step.


1. The yy-intercept

The yy-intercept is found by evaluating f(0)f(0). Substituting x=0x = 0:

f(0)=2(0)2+7(0)153(0)210(0)+3=153=5f(0) = \frac{2(0)^2 + 7(0) - 15}{3(0)^2 - 10(0) + 3} = \frac{-15}{3} = -5

So, the yy-intercept is at the point (0, -5).


2. The xx-intercepts

The xx-intercepts occur where the numerator equals zero, i.e., 2x2+7x15=02x^2 + 7x - 15 = 0. Solve this quadratic equation using the quadratic formula:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Here, a=2a = 2, b=7b = 7, c=15c = -15:

x=7±724(2)(15)2(2)=7±49+1204=7±1694x = \frac{-7 \pm \sqrt{7^2 - 4(2)(-15)}}{2(2)} = \frac{-7 \pm \sqrt{49 + 120}}{4} = \frac{-7 \pm \sqrt{169}}{4}

x=7±134x = \frac{-7 \pm 13}{4}

x=7+134=64=32,x=7134=204=5x = \frac{-7 + 13}{4} = \frac{6}{4} = \frac{3}{2}, \quad x = \frac{-7 - 13}{4} = \frac{-20}{4} = -5

So, the xx-intercepts are at the points (32,0)\left(\frac{3}{2}, 0\right) and (5,0)(-5, 0).


3. Vertical asymptotes

Vertical asymptotes occur where the denominator equals zero, i.e., 3x210x+3=03x^2 - 10x + 3 = 0. Solve this quadratic equation using the quadratic formula:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Here, a=3a = 3, b=10b = -10, c=3c = 3:

x=(10)±(10)24(3)(3)2(3)=10±100366=10±646x = \frac{-(-10) \pm \sqrt{(-10)^2 - 4(3)(3)}}{2(3)} = \frac{10 \pm \sqrt{100 - 36}}{6} = \frac{10 \pm \sqrt{64}}{6}

x=10+86=186=3,x=1086=26=13x = \frac{10 + 8}{6} = \frac{18}{6} = 3, \quad x = \frac{10 - 8}{6} = \frac{2}{6} = \frac{1}{3}

So, the vertical asymptotes are at x=3x = 3 and x=13x = \frac{1}{3}.


Final Results:

  1. yy-intercept: (0,5)(0, -5)
  2. xx-intercepts: (32,0)\left(\frac{3}{2}, 0\right) and (5,0)(-5, 0)
  3. Vertical asymptotes: x=3x = 3 and x=13x = \frac{1}{3}

Do you have any questions or need further details?
Here are some related questions for further exploration:

  1. What are the horizontal asymptotes of this function?
  2. How would you graph this function based on the intercepts and asymptotes?
  3. What happens to the function as xx \to \infty or xx \to -\infty?
  4. Can you confirm the domain of f(x)f(x) based on the asymptotes?
  5. How can the behavior near the asymptotes be analyzed?

Tip: Always factorize where possible to simplify finding intercepts and asymptotes.

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Functions
Quadratic Equations

Formulas

y-intercept: f(0) = (numerator evaluated at x = 0) / (denominator evaluated at x = 0)
x-intercepts: Solve numerator = 0
Vertical asymptotes: Solve denominator = 0
Quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

Theorems

Quadratic formula

Suitable Grade Level

Grades 10-12