Math Problem Statement

solve part b

Rewrite the rational function y = x / (x^2 + 1) into the form y = r(x) + s(x) / q(x), find its asymptotes, and sketch its graph.

Solution

For part (b), we are asked to rewrite the rational function y=xx2+1y = \frac{x}{x^2 + 1} into the form y=r(x)+s(x)q(x)y = r(x) + \frac{s(x)}{q(x)}, where r(x)r(x) is a polynomial part and s(x)q(x)\frac{s(x)}{q(x)} is the remainder. Additionally, we will identify asymptotes and roughly sketch the graph based on the given information.

Step 1: Rewrite the function

In this case, the function y=xx2+1y = \frac{x}{x^2 + 1} is already in its simplest form, and it cannot be divided further into a polynomial part r(x)r(x) because the degree of the denominator (2) is greater than the degree of the numerator (1). Therefore, r(x)=0r(x) = 0, and the whole function is already of the form s(x)q(x)\frac{s(x)}{q(x)} with:

  • s(x)=xs(x) = x
  • q(x)=x2+1q(x) = x^2 + 1.

Step 2: Asymptotes

For asymptotes, we look at the behavior of the function as xx \to \infty or xx \to -\infty:

  • Horizontal asymptote: Since the degree of the denominator is higher than the degree of the numerator, the function tends to 0 as xx \to \infty. Thus, there is a horizontal asymptote at y=0y = 0.
  • Vertical asymptote: Vertical asymptotes occur where the denominator is zero, but x2+1=0x^2 + 1 = 0 has no real roots. Therefore, there are no vertical asymptotes.

Step 3: Rough sketch of the graph

  • The function has a horizontal asymptote at y=0y = 0.
  • The function is symmetric with respect to the y-axis because it is an odd function.
  • At x=0x = 0, the value of the function is y(0)=0y(0) = 0, meaning it passes through the origin.
  • For large positive and negative values of xx, the function approaches 0.

This information suggests that the graph will approach the x-axis from both the left and right but will never cross the asymptote y=0y = 0 at infinity.

Would you like further details or clarifications?

5 Related Questions:

  1. How do you determine horizontal asymptotes for rational functions?
  2. Why doesn't the function y=xx2+1y = \frac{x}{x^2 + 1} have a vertical asymptote?
  3. What happens to the graph of y=xx2+1y = \frac{x}{x^2 + 1} as xx \to \infty?
  4. How do you find the intercepts of rational functions like y=xx2+1y = \frac{x}{x^2 + 1}?
  5. What are the symmetries of the function y=xx2+1y = \frac{x}{x^2 + 1}?

Tip:

To identify the horizontal asymptote of a rational function, always compare the degrees of the numerator and denominator.

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Math Problem Analysis

Mathematical Concepts

Rational functions
Asymptotes
Function behavior
Graphing functions

Formulas

Horizontal asymptote: Compare degrees of numerator and denominator

Theorems

Degree comparison for horizontal asymptotes

Suitable Grade Level

Grades 10-12