Math Problem Statement

A first-order plant P(s) = 1/(s+1) is connected in unity feedback configuration with a PI controller. If the controller gains are K_i =2 and K_p =1, then which of the following statements are true?

A) The closed loop system has zero steady-state error for a step input.

B) The closed loop system has complex conjugate poles at s=-1 \pm j .

C) The closed loop system is a first-order system.

D) The closed loop system has a zero in the LHP.

Question 1Select one:

a. Statements A, B, C and D are all correct.

b. Only statement C is correct.

c. Statements A, B, and D are correct, and C is incorrect.

d. Only statement D is correct.

e. Only statement A is correct.

f. Only statement B is correct.

Solution

To analyze the given system and determine which of the statements are true, we will first derive the transfer function of the closed-loop system with the given PI controller.

Step 1: Define the System

  • The plant is P(s)=1s+1P(s) = \frac{1}{s+1}.
  • The PI controller is given by C(s)=Kp+Kis=1+2s=s+2sC(s) = K_p + \frac{K_i}{s} = 1 + \frac{2}{s} = \frac{s + 2}{s}.

Step 2: Open-Loop Transfer Function

The open-loop transfer function is: GOL(s)=C(s)P(s)=s+2s1s+1=s+2s(s+1)G_{\text{OL}}(s) = C(s) \cdot P(s) = \frac{s + 2}{s} \cdot \frac{1}{s+1} = \frac{s + 2}{s(s + 1)}

Step 3: Closed-Loop Transfer Function

The closed-loop transfer function is: GCL(s)=GOL(s)1+GOL(s)=s+2s(s+1)1+s+2s(s+1)=s+2s2+2s+2G_{\text{CL}}(s) = \frac{G_{\text{OL}}(s)}{1 + G_{\text{OL}}(s)} = \frac{\frac{s + 2}{s(s + 1)}}{1 + \frac{s + 2}{s(s + 1)}} = \frac{s + 2}{s^2 + 2s + 2}

Step 4: Analyze the Statements

Statement A: Zero steady-state error for a step input

  • A PI controller generally ensures zero steady-state error for a step input because it introduces an integrator, making the system type 1.
  • True.

Statement B: Complex conjugate poles at s=1±js = -1 \pm j

  • To find the poles, solve the characteristic equation s2+2s+2=0s^2 + 2s + 2 = 0.
  • The roots are s=1±js = -1 \pm j.
  • True.

Statement C: The closed-loop system is a first-order system

  • The characteristic equation is quadratic (s2+2s+2s^2 + 2s + 2), indicating a second-order system.
  • False.

Statement D: The closed-loop system has a zero in the left-half plane (LHP)

  • The numerator of GCL(s)G_{\text{CL}}(s) is s+2s + 2, which gives a zero at s=2s = -2.
  • This zero is in the LHP.
  • True.

Conclusion

The correct answer is:

c. Statements A, B, and D are correct, and C is incorrect.


Do you want details or have any questions?

Here are 5 related questions:

  1. How does the presence of a PI controller affect the stability of a system?
  2. What is the significance of the system poles being complex conjugates?
  3. Why does a PI controller ensure zero steady-state error for a step input?
  4. How does the location of a zero in the left-half plane affect system behavior?
  5. Can a system with a second-order characteristic equation be considered first-order under any conditions?

Tip: Understanding the pole-zero configuration of a system helps in predicting its time-domain and frequency-domain behavior.

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Math Problem Analysis

Mathematical Concepts

Control Systems
Transfer Functions
PID Controllers

Formulas

Transfer function of a PI controller
Closed-loop transfer function

Theorems

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Suitable Grade Level

Advanced Undergraduate