Math Problem Statement

f(x) = x²+ 1 at the point (0,1)

Solution

It looks like you want to analyze the function f(x)=x2+1f(x) = x^2 + 1 at the point (0,1)(0, 1). Let me clarify the context for you:

  • The function f(x)=x2+1f(x) = x^2 + 1 is a parabola that opens upwards.
  • The point (0,1)(0, 1) is where x=0x = 0 and f(0)=1f(0) = 1, so this is a valid point on the curve.

Would you like to explore the slope of the curve (i.e., the derivative) at this point, or is there another specific aspect of the function you'd like to analyze?

Let me know if you have further questions or need more details. Here are a few additional questions we could explore:

  1. What is the derivative of the function f(x)=x2+1f(x) = x^2 + 1?
  2. How do we find the slope of the tangent line at (0,1)(0, 1)?
  3. What is the concavity of the function f(x)=x2+1f(x) = x^2 + 1?
  4. How do we calculate the area under the curve from x=1x = -1 to x=1x = 1?
  5. What would happen if we shift the graph of f(x)=x2+1f(x) = x^2 + 1 vertically or horizontally?

Tip: To find the slope of the tangent line at any point on a function, you can compute the derivative and evaluate it at the given xx-value.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Quadratic Functions
Tangent Lines

Formulas

f'(x) = 2x
f(x) = x² + 1

Theorems

Fundamental Theorem of Calculus
Derivative of a quadratic function

Suitable Grade Level

Grades 10-12