Math Problem Statement

Identify all correct statements regarding the function y = x^3.

Solution

Based on the uploaded images, I will interpret the mathematical statements and verify their correctness regarding the function y=x3y = x^3.

Key properties of y=x3y = x^3:

  1. First derivative: y(x)=3x2y'(x) = 3x^2

    • y(x)=0y'(x) = 0 at x=0x = 0, which is a critical point.
  2. Second derivative: y(x)=6xy''(x) = 6x

    • y(x)>0y''(x) > 0 for x>0x > 0 (concave up).
    • y(x)<0y''(x) < 0 for x<0x < 0 (concave down).
    • y(0)=0y''(0) = 0, so x=0x = 0 is a point of inflection.
  3. Behavior at x=0x = 0:

    • y=x3y = x^3 is continuous and differentiable everywhere, including at x=0x = 0.

Analysis of the statements:

  1. First statement: Since y(x)>0y''(x) > 0 on (0,+)(0, +\infty), the function is strictly concave up on this interval. The statement says "strictly concave down," which is incorrect.

  2. Second statement: The function y=x3y = x^3 is continuous at x=0x = 0. This statement is correct.

  3. Third statement: On (,0)(-\infty, 0), y(x)<0y''(x) < 0, so the function is concave down on this interval. This statement matches, so it is correct.

  4. Fourth statement: At x=0x = 0, the second derivative y(0)=0y''(0) = 0, and x=0x = 0 is not a critical point of the second kind. The statement is incorrect.

  5. Fifth statement: The second derivative y(0)=0y''(0) = 0, which is correct.

  6. Sixth statement: On (,0)(-\infty, 0), y(x)<0y''(x) < 0, so it is concave down, not concave up. This statement is incorrect.

  7. Seventh statement: The first derivative y(0)=0y'(0) = 0, which exists. The statement is correct.

  8. Eighth statement: The second derivative y(0)=0y''(0) = 0, and it exists. The statement claiming non-existence is incorrect.

Correct Statements:

  1. The function is continuous at x=0x = 0.
  2. The function is concave down on (,0)(-\infty, 0).
  3. y(0)y'(0) exists and equals 00.
  4. y(0)y''(0) exists and equals 00.

Would you like detailed explanations for each statement or assistance with additional concepts? Here are five questions you might explore further:

  1. What defines a point of inflection for a function like y=x3y = x^3?
  2. How does the second derivative test classify critical points?
  3. Can a function be both concave up and concave down at different intervals?
  4. Why is continuity important for analyzing derivatives at a point?
  5. How does y=x3y = x^3 compare to higher-degree odd functions?

Tip: Always examine the behavior of derivatives to confirm concavity and points of inflection.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivative Analysis
Concavity
Points of Inflection

Formulas

First derivative: y'(x) = 3x^2
Second derivative: y''(x) = 6x

Theorems

Concavity and the Second Derivative Test
Definition of a Point of Inflection

Suitable Grade Level

Grades 10-12