Math Problem Statement
a. Complete an amortization schedule for a $17,000 loan to be repaid in equal installments at the end of each of the next three years. The interest rate is 10% compounded annually. Round all answers to the nearest cent.
Beginning
Repayment
Ending
Year
Balance
Payment
Interest
of Principal
Balance
1
$ fill in the blank 2
$ fill in the blank 3
$ fill in the blank 4
$ fill in the blank 5
$ fill in the blank 6
2
$ fill in the blank 7
$ fill in the blank 8
$ fill in the blank 9
$ fill in the blank 10
$ fill in the blank 11
3
$ fill in the blank 12
$ fill in the blank 13
$ fill in the blank 14
$ fill in the blank 15
$
Solution
To solve for the amortization schedule, we can follow these steps:
Step 1: Determine the Annual Payment
The loan amount is $17,000, and the interest rate is 10% per year. The loan is to be repaid in equal installments at the end of each of the next three years. This is a typical case for an amortization schedule using the formula for the payment on an amortizing loan:
Where:
- = annual payment
- = principal amount (loan balance), which is $17,000
- = interest rate per period (10% or 0.10)
- = number of periods (3 years)
Let's plug the values into the formula to find the annual payment:
Now, we'll compute the exact value for the payment:
So, the annual payment is approximately $6,834.14.
Step 2: Set up the Amortization Table
Now we can set up the amortization table. For each year, we'll calculate:
- Interest for the year: The interest for each year is calculated as the beginning balance multiplied by the interest rate (10%).
- Principal repaid: The principal repayment is the total payment minus the interest for the year.
- Ending balance: The ending balance is the beginning balance minus the principal repaid.
We'll now create the amortization schedule.
Amortization Schedule
Year 1:
- Beginning Balance: $17,000.00
- Payment: $6,834.14
- Interest: $17,000 × 0.10 = $1,700.00
- Principal Repayment: $6,834.14 - $1,700.00 = $5,134.14
- Ending Balance: $17,000.00 - $5,134.14 = $11,865.86
Year 2:
- Beginning Balance: $11,865.86
- Payment: $6,834.14
- Interest: $11,865.86 × 0.10 = $1,186.59
- Principal Repayment: $6,834.14 - $1,186.59 = $5,647.55
- Ending Balance: $11,865.86 - $5,647.55 = $6,218.31
Year 3:
- Beginning Balance: $6,218.31
- Payment: $6,834.14
- Interest: $6,218.31 × 0.10 = $621.83
- Principal Repayment: $6,834.14 - $621.83 = $6,212.31
- Ending Balance: $6,218.31 - $6,212.31 = $0.00
Final Amortization Table
Year | Beginning Balance | Payment | Interest | Principal Repaid | Ending Balance |
---|---|---|---|---|---|
1 | $17,000.00 | $6,834.14 | $1,700.00 | $5,134.14 | $11,865.86 |
2 | $11,865.86 | $6,834.14 | $1,186.59 | $5,647.55 | $6,218.31 |
3 | $6,218.31 | $6,834.14 | $621.83 | $6,212.31 | $0.00 |
Let me know if you need further details or have any other questions!
Here are five related questions:
- How would the amortization schedule change if the loan term were 5 years instead of 3 years?
- What happens to the total interest paid over the life of the loan if the interest rate increases to 12%?
- How can the formula for calculating payments be adapted for loans with different compounding periods (e.g., monthly or quarterly)?
- What would happen if you made an extra payment during one of the years?
- How can you use the amortization schedule to calculate the total cost of a loan over its term?
Tip: The total interest paid on the loan can be found by subtracting the principal amount from the total of all payments made over the life of the loan.
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Math Problem Analysis
Mathematical Concepts
Amortization
Loan Repayment
Interest Calculation
Algebra
Formulas
PMT = P * r / (1 - (1 + r)^(-n))
Theorems
Amortization formula
Suitable Grade Level
Grades 11-12
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