Math Problem Statement

Consider the series ∑ (n=1 to ∞) ((-1)^n) / (8^n * n). Part a) Show that the series converges. Part b) How many terms of the series are needed so that the error in the partial approximation is no more than 0.00005?

Solution

Let's address the problem step by step:


Part (a): Show that the series converges

The given series is:

n=1(1)n8nn\sum_{n=1}^{\infty} \frac{(-1)^n}{8^n n}

This is an alternating series, as it has the term (1)n(-1)^n. To prove convergence, we can use the Alternating Series Test (Leibniz's Test). According to this test, an alternating series converges if:

  1. The terms an=18nna_n = \frac{1}{8^n n} decrease monotonically (i.e., an+1<ana_{n+1} < a_n for all nn).
  2. limnan=0\lim_{n \to \infty} a_n = 0.

Step 1: Verify an=18nna_n = \frac{1}{8^n n} decreases monotonically

For ana_n to decrease monotonically, the denominator 8nn8^n n must grow faster than the numerator (which is constant, 11) as nn increases. Clearly:

an+1=18n+1(n+1)<an=18nn,because 8n+1>8n and (n+1)>n.a_{n+1} = \frac{1}{8^{n+1}(n+1)} < a_n = \frac{1}{8^n n}, \quad \text{because } 8^{n+1} > 8^n \text{ and } (n+1) > n.

Thus, ana_n is monotonically decreasing.

Step 2: Compute limnan\lim_{n \to \infty} a_n

limnan=limn18nn.\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{1}{8^n n}.

Since 8n8^n grows exponentially while nn grows linearly, the denominator goes to infinity, making the limit 00.

Thus, both conditions of the Alternating Series Test are satisfied, so the series converges.


Part (b): Find how many terms are needed for the error to be no more than 0.000050.00005

For an alternating series, the error RnR_n after nn terms is bounded by the first omitted term:

Rnan+1.|R_n| \leq a_{n+1}.

Here, an=18nna_n = \frac{1}{8^n n}. We need an+10.00005a_{n+1} \leq 0.00005, or:

18n+1(n+1)0.00005.\frac{1}{8^{n+1}(n+1)} \leq 0.00005.

Rearranging:

8n+1(n+1)10.00005=20000.8^{n+1}(n+1) \geq \frac{1}{0.00005} = 20000.

Let’s solve this inequality numerically to find nn:

  1. Start testing n=1,2,3,n = 1, 2, 3, \dots until the inequality is satisfied.
  2. For n=6n = 6: 86+1(6+1)=877=20971527=14680064, which is greater than 20000.8^{6+1}(6+1) = 8^7 \cdot 7 = 2097152 \cdot 7 = 14680064, \text{ which is greater than 20000.}

Thus, at least 6 terms are needed to ensure the error is no more than 0.000050.00005.


Would you like detailed numerical verification or further explanation of any step?

Related Questions:

  1. What are other convergence tests that could verify this series' convergence?
  2. How can we compute the sum of the first nn terms of this series explicitly?
  3. What happens to the error if we include one additional term?
  4. How does the alternating series test compare to the ratio test in this scenario?
  5. What practical applications could such alternating series have in mathematics or physics?

Tip: For numerical problems involving series, always double-check your calculations for higher precision, especially when setting error bounds.

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Math Problem Analysis

Mathematical Concepts

Alternating Series
Convergence of Series
Error Bounds

Formulas

Alternating Series Error: |R_n| ≤ a_(n+1)
General Term: a_n = 1 / (8^n * n)

Theorems

Alternating Series Test (Leibniz's Test)

Suitable Grade Level

Undergraduate Mathematics