When rolling two six-sided dice, each die has 6 faces, numbered from 1 to 6. The total number of possible outcomes when rolling the two dice is the product of the number of faces on each die:

$6 \times 6 = 36 \text{ possible outcomes.}$

These outcomes can be organized as pairs $(a, b)$, where $a$ is the result of the first die, and $b$ is the result of the second die. Here are all the possible outcomes:

1. (1, 1)
2. (1, 2)
3. (1, 3)
4. (1, 4)
5. (1, 5)
6. (1, 6)
7. (2, 1)
8. (2, 2)
9. (2, 3)
10. (2, 4)
11. (2, 5)
12. (2, 6)
13. (3, 1)
14. (3, 2)
15. (3, 3)
16. (3, 4)
17. (3, 5)
18. (3, 6)
19. (4, 1)
20. (4, 2)
21. (4, 3)
22. (4, 4)
23. (4, 5)
24. (4, 6)
25. (5, 1)
26. (5, 2)
27. (5, 3)
28. (5, 4)
29. (5, 5)
30. (5, 6)
31. (6, 1)
32. (6, 2)
33. (6, 3)
34. (6, 4)
35. (6, 5)
36. (6, 6)

Summary:

There are 36 possible outcomes when rolling two six-sided dice.

Would you like more details or have any other questions?

Here are some additional related questions:

1. What is the probability of rolling a sum of 7 with two dice?
2. How many outcomes result in a double (same number on both dice)?
3. What is the probability of rolling a sum of 12 with two dice?
4. How many possible outcomes result in a sum less than 5?
5. What is the probability of rolling an even sum with two dice?
6. How many outcomes result in a sum greater than 8?
7. What is the probability of rolling a sum of 3 or 11 with two dice?
8. How would the outcomes change if one die had more than 6 faces?

Tip: For probability questions involving dice, it's helpful to visualize the possible outcomes using a grid or table to count occurrences easily.