Math Problem Statement

Solve the exercises from the image involving algebraic expressions, quadratic equations, and areas of geometric shapes.

Solution

I see the exercises in the uploaded image. I'll analyze them one by one and provide solutions along with detailed explanations.


Exercise 5

Expression:

C=(5x3)2(2x1)(5x3)C = (5x - 3)^2 - (2x - 1)(5x - 3)

  1. Develop, simplify, and order CC:

    • Expand (5x3)2=25x230x+9(5x - 3)^2 = 25x^2 - 30x + 9
    • Expand (2x1)(5x3)=10x211x+3(2x - 1)(5x - 3) = 10x^2 - 11x + 3
    • Subtract:
      C=(25x230x+9)(10x211x+3)C = (25x^2 - 30x + 9) - (10x^2 - 11x + 3) C=25x230x+910x2+11x3C = 25x^2 - 30x + 9 - 10x^2 + 11x - 3 C=15x219x+6C = 15x^2 - 19x + 6
  2. Calculate CC for x=2x = -2:

    Substitute x=2x = -2 into C=15x219x+6C = 15x^2 - 19x + 6: C=15(2)219(2)+6C = 15(-2)^2 - 19(-2) + 6 C=15(4)+38+6=60+38+6=104C = 15(4) + 38 + 6 = 60 + 38 + 6 = 104

  3. Factorize CC:

    Factor 15x219x+615x^2 - 19x + 6: C=(3x2)(5x3)C = (3x - 2)(5x - 3)

  4. Solve the equation (5x3)(23x)=0(5x - 3)(2 - 3x) = 0:

    Set each factor to zero:

    • 5x3=0    x=355x - 3 = 0 \implies x = \frac{3}{5}
    • 23x=0    x=232 - 3x = 0 \implies x = \frac{2}{3}

    Solutions: x=35,23x = \frac{3}{5}, \frac{2}{3}


Exercise 6

  1. Calculate A=109×91A = 109 \times 91:

    Use the difference of squares:
    109×91=(100+9)(1009)=100292=1000081=9919109 \times 91 = (100 + 9)(100 - 9) = 100^2 - 9^2 = 10000 - 81 = 9919

  2. Calculate B=125227522B = 1252^2 - 752^2:

    Use the difference of squares:
    125227522=(1252+752)(1252752)=2004×500=10020001252^2 - 752^2 = (1252 + 752)(1252 - 752) = 2004 \times 500 = 1002000

  3. Calculate C=1032C = 103^2:

    Use expansion:
    1032=(100+3)2=1002+2(100)(3)+32=10000+600+9=10609103^2 = (100 + 3)^2 = 100^2 + 2(100)(3) + 3^2 = 10000 + 600 + 9 = 10609


Exercise 7

  1. Express the area A1A_1 of rectangle ABCDABCD:

    The length of ABCDABCD is 3x53x - 5 and the width is 2x+12x + 1:
    A1=(3x5)(2x+1)A_1 = (3x - 5)(2x + 1)

  2. Express the area A2A_2 of polygon EFGHIJEFGHIJ:

    Subtract the area of square FGHIFGHI (side 3x73x - 7) from rectangle EFGJEFGJ (dimensions 3x73x - 7 and 3x53x - 5):
    A2=(3x7)(3x5)(3x7)2A_2 = (3x - 7)(3x - 5) - (3x - 7)^2 Factorize: A2=(3x7)((3x5)(3x7))=(3x7)(2)A_2 = (3x - 7)\big((3x - 5) - (3x - 7)\big) = (3x - 7)(2) A2=2(3x7)A_2 = 2(3x - 7)

  3. Solve for xx when A1=A2A_1 = A_2:

    Equate A1A_1 and A2A_2:
    (3x5)(2x+1)=2(3x7)(3x - 5)(2x + 1) = 2(3x - 7) Expand and simplify: 6x215x+3x5=6x146x^2 - 15x + 3x - 5 = 6x - 14 6x212x+9=06x^2 - 12x + 9 = 0 Factorize: 3(2x24x+3)=03(2x^2 - 4x + 3) = 0 Solve using the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}


Would you like further details on any step, or clarification? 😊

Related Questions:

  1. Can you derive a shortcut for (a+b)2(ab)2(a + b)^2 - (a - b)^2?
  2. What are the general steps for factoring quadratics?
  3. How do you verify solutions for quadratic equations graphically?
  4. Can you solve (x+1)2=4(x + 1)^2 = 4 for real and complex xx?
  5. How do the expressions for area depend on specific values of xx?

Tip:

When solving quadratic equations, always check whether factoring or the quadratic formula is more efficient!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Area of Shapes

Formulas

(a + b)^2 = a^2 + 2ab + b^2
Difference of squares: a^2 - b^2 = (a + b)(a - b)
Quadratic equation: ax^2 + bx + c = 0
Area of a rectangle: length × width

Theorems

Quadratic Formula
Factoring Quadratics
Properties of the Difference of Squares

Suitable Grade Level

Grades 8-10