Let's define the initial amount of water in containers $A$ and $B$ as $x$ liters each. Since both containers had the same initial amount of water, we know:

• Amount of water in container $A$ after usage: $x - 25.5$ liters.
• Amount of water in container $B$ after usage: $x - 44.5$ liters.

After using some water, container $A$ has 5 times as much water as container $B$. This gives us the equation:

$x - 25.5 = 5(x - 44.5)$

Let's solve this equation step-by-step:

1. Expand the equation:

$x - 25.5 = 5x - 222.5$

2. Rearrange to isolate $x$ on one side:

$x - 5x = -222.5 + 25.5$

$-4x = -197$

3. Divide by -4:

$x = \frac{-197}{-4}$

$x = 49.25$

Therefore, the initial amount of water in container $B$ was 49.25 liters.

Would you like more details or have any questions?

Here are 5 related questions to consider:

1. What if the water usage amounts were different for containers A and B?
2. How would the problem change if container A had twice the initial amount of water as container B?
3. Can you solve similar problems with more than two containers?
4. What if we only knew the ratio of the remaining water instead of the actual amounts?
5. How would this problem change if water was added instead of removed?

Tip: Always double-check the logic in word problems by translating them into clear equations step-by-step.