To find the average acceleration, we can use the kinematic equation that relates initial velocity, final velocity, acceleration, and distance:

$v_f^2 = v_i^2 + 2a d$

Where:

• $v_f = 6.3 \, \text{m/s}$ (final velocity),
• $v_i = 63 \, \text{m/s}$ (initial velocity),
• $d = 755 \, \text{m}$ (distance),
• $a$ is the average acceleration (which we need to find).

We are given that the direction is northward, and since the plane is slowing down, the acceleration will be negative (deceleration). Now, we can rearrange the equation to solve for $a$:

$a = \frac{v_f^2 - v_i^2}{2d}$

Substituting the given values:

$a = \frac{(6.3)^2 - (63)^2}{2 \times 755}$

Now, let's calculate this:

$a = \frac{39.69 - 3969}{1510}$ $a = \frac{-3929.31}{1510}$ $a \approx -2.60 \, \text{m/s}^2$

Conclusion:

The average acceleration of the plane is approximately -2.60 m/s². The negative sign indicates that the acceleration is directed southward (opposite to the northward motion of the plane).

Would you like more details on the steps, or is this clear? Here are a few related questions for further exploration:

1. What would the stopping distance be if the plane had a different initial velocity (e.g., 100 m/s)?
2. How does the concept of deceleration apply in other motion scenarios, like a car braking to a stop?
3. How does friction between the plane's wheels and the runway affect the acceleration during landing?
4. How would the acceleration change if the plane were landing on a downhill runway?
5. What is the difference between average acceleration and instantaneous acceleration?

Tip: Always pay attention to the signs of your velocities and accelerations, as they give you information about the direction of motion.