Math Problem Statement
The present ages of A and B are in the ratio of 6:4. 5 years ago their ratio were in the 5:3. How old is A now?
Solution
Let the present ages of A and B be and respectively, where is a constant multiplier for the ratio.
Step 1: Form equation based on the information
We know that 5 years ago, the ratio of their ages was 5:3. Therefore:
Step 2: Solve the equation
Cross-multiply to eliminate the fractions:
Expanding both sides:
Step 3: Isolate
Simplify and move the terms involving to one side:
Step 4: Calculate A's age
Since , the present age of A is:
So, A is 30 years old.
Do you want further details or have any questions?
Here are 5 related questions:
- What is B's current age?
- How old was A five years ago?
- How will the ratio of their ages change in 10 years?
- Can we find the total of their ages using the given information?
- How would the solution change if the ratios were different?
Tip: When solving problems involving ratios and ages, always express ages in terms of a single variable for easier manipulation.
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Math Problem Analysis
Mathematical Concepts
Algebra
Ratios
Linear Equations
Formulas
Present ages: A = 6x, B = 4x
5 years ago: (A - 5)/(B - 5) = 5/3
Theorems
Cross-multiplication
Linear Equation Solving
Suitable Grade Level
Grades 6-8
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