Math Problem Statement

The present ages of A and B are in the ratio of 6:4. 5 years ago their ratio were in the 5:3. How old is A now?

Solution

Let the present ages of A and B be 6x6x and 4x4x respectively, where xx is a constant multiplier for the ratio.

Step 1: Form equation based on the information

We know that 5 years ago, the ratio of their ages was 5:3. Therefore:

6x54x5=53\frac{6x - 5}{4x - 5} = \frac{5}{3}

Step 2: Solve the equation

Cross-multiply to eliminate the fractions:

3(6x5)=5(4x5)3(6x - 5) = 5(4x - 5)

Expanding both sides:

18x15=20x2518x - 15 = 20x - 25

Step 3: Isolate xx

Simplify and move the terms involving xx to one side:

18x20x=25+1518x - 20x = -25 + 15

2x=10-2x = -10

x=5x = 5

Step 4: Calculate A's age

Since x=5x = 5, the present age of A is:

6x=6×5=306x = 6 \times 5 = 30

So, A is 30 years old.


Do you want further details or have any questions?

Here are 5 related questions:

  1. What is B's current age?
  2. How old was A five years ago?
  3. How will the ratio of their ages change in 10 years?
  4. Can we find the total of their ages using the given information?
  5. How would the solution change if the ratios were different?

Tip: When solving problems involving ratios and ages, always express ages in terms of a single variable for easier manipulation.

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Math Problem Analysis

Mathematical Concepts

Algebra
Ratios
Linear Equations

Formulas

Present ages: A = 6x, B = 4x
5 years ago: (A - 5)/(B - 5) = 5/3

Theorems

Cross-multiplication
Linear Equation Solving

Suitable Grade Level

Grades 6-8