Math Problem Statement
accurate answers and show working
Solution
The problem involves the formula for the amount of Advil in the bloodstream over time, given by:
where is time in minutes and is the amount in mg.
The problem requires the following:
(a) Graph the function for in .
To do this, I will calculate at various points and plot the function over the interval.
(b) Find when the drug reaches its maximum level in the bloodstream.
This involves finding the critical points of by solving , then determining the maximum.
(c) Find when the drug falls below .
This involves solving for .
Let me calculate and graph the results step by step. numpy as np import matplotlib.pyplot as plt from scipy.optimize import fsolve
Define the function A(t)
def A(t): return 33.6 * (np.exp(-0.008 * t) - np.exp(-0.12 * t))
Define the derivative A'(t) for finding critical points
def A_prime(t): return 33.6 * (-0.008 * np.exp(-0.008 * t) + 0.12 * np.exp(-0.12 * t))
Generate values of t and corresponding A(t) for the graph
t_values = np.linspace(0, 240, 1000) A_values = A(t_values)
Plot the graph of A(t)
plt.figure(figsize=(10, 6)) plt.plot(t_values, A_values, label="A(t) = 33.6(e^(-0.008t) - e^(-0.12t))") plt.title("Graph of Drug Concentration in Bloodstream") plt.xlabel("Time (t) in minutes") plt.ylabel("Amount of Drug (A) in mg") plt.grid() plt.axhline(y=7.5, color='red', linestyle='--', label='A(t) = 7.5 mg') plt.legend() plt.show()
Find the time of maximum concentration by solving A'(t) = 0
t_critical = fsolve(A_prime, 100) # Initial guess of 100 minutes
Find when A(t) = 7.5 by solving A(t) - 7.5 = 0
def A_minus_7_5(t): return A(t) - 7.5
t_below_7_5 = fsolve(A_minus_7_5, [10, 200]) # Initial guesses
Maximum value of A(t) at t_critical
A_max = A(t_critical[0])
t_critical[0], A_max, t_below_7_5### Solutions: (a) Graph: The graph of for is shown above. The red dashed line represents the threshold .
(b) Maximum Level:
- The drug reaches its maximum level at .
- The maximum amount is approximately .
(c) Below 7.5 mg:
- The drug falls below at two points:
- (on the way up),
- (on the way down).
Observations:
- The concentration quickly increases and peaks around .
- After , the concentration falls below , which might indicate when the drug becomes less effective.
Let me know if you'd like detailed explanations of the calculations, or if you have further questions!
Related Questions:
- How is the derivative computed to find critical points?
- How does exponential decay influence drug concentration over time?
- What does the area under the curve of represent in this context?
- How does changing the constants or affect the drug's behavior?
- What is the half-life of this drug, and how is it computed?
Tip:
To better analyze exponential functions like , study their behavior at critical points (e.g., ), which helps with both graphing and solving related equations.
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Math Problem Analysis
Mathematical Concepts
Exponential Functions
Critical Points
Graphing
Numerical Solutions
Formulas
A(t) = 33.6(e^(-0.008t) - e^(-0.12t))
Derivative for critical points: A'(t) = d/dt [33.6(e^(-0.008t) - e^(-0.12t))]
A(t) = 7.5 (to find when drug falls below 7.5 mg)
Theorems
Critical Points in Calculus
Exponential Decay Properties
Suitable Grade Level
Grades 11-12, Early College