https://file.aiquickdraw.com/mathbot/file/1729607622944dncznsk6.jpg

The image you uploaded shows the following mathematical expression:

\[
\frac{9}{16} + \frac{5}{7}
\]

Let's solve this step by step.

### Step 1: Find a common denominator
The denominators are 16 and 7. The least common denominator (LCD) of 16 and 7 is the product of the two, since they are coprime:

\[
\text{LCD} = 16 \times 7 = 112
\]

### Step 2: Convert each fraction to have the same denominator
We convert both fractions so that their denominators are 112.

For \(\frac{9}{16}\), multiply both the numerator and denominator by 7:

\[
\frac{9}{16} = \frac{9 \times 7}{16 \times 7} = \frac{63}{112}
\]

For \(\frac{5}{7}\), multiply both the numerator and denominator by 16:

\[
\frac{5}{7} = \frac{5 \times 16}{7 \times 16} = \frac{80}{112}
\]

### Step 3: Add the fractions
Now that the denominators are the same, we can add the numerators:

\[
\frac{63}{112} + \frac{80}{112} = \frac{63 + 80}{112} = \frac{143}{112}
\]

### Step 4: Simplify the result
\(\frac{143}{112}\) is already in its simplest form, since 143 and 112 have no common factors other than 1.

Thus, the final answer is:

\[
\frac{143}{112}
\]

If you prefer this result as a mixed number, you can convert it:

\[
\frac{143}{112} = 1 \frac{31}{112}
\]

Let me know if you'd like further explanation or details!

Here are some related questions you might want to explore:

1. How do you find the least common denominator for different sets of fractions?
2. What are the steps to convert an improper fraction into a mixed number?
3. How can you simplify a fraction after addition?
4. What are some common methods to add fractions with unlike denominators?
5. How do you check if two fractions are in their simplest form?

**Tip**: When adding fractions, always look for the smallest common denominator to make calculations easier.

Learn how to add fractions with unlike denominators using the example of 9/16 + 5/7. This detailed solution covers finding the least common denominator, converting fractions, and simplifying the result. Ideal for Grades 5-7.

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