Math Problem Statement

𝐴=𝑃(1+π‘Ÿπ‘›)𝑛𝑑 and 𝐴=π‘ƒπ‘’π‘Ÿπ‘‘ to solve the exercises below. Round your answer to the nearest cent. Find the accumulated value of an investment of $14490 for 7 years at an annual interest rate of 7.1% if the money is (a) compounded semiannually: functionsequation editor dollars (b) compounded quarterly: functionsequation editor dollars (c) compounded monthly: functionsequation editor dollars (d) compounded continuously: functionsequation editor dollars

Solution

To solve these problems, we’ll use both compound interest formulas:

  1. For compounding a finite number of times per year:
    A=P(1+rn)ntA = P \left(1 + \frac{r}{n}\right)^{nt} where:

    • AA is the accumulated amount,
    • PP is the principal (initial amount),
    • rr is the annual interest rate,
    • nn is the number of compounding periods per year,
    • tt is the time in years.
  2. For continuous compounding:
    A=PertA = P e^{rt}

Given:

  • P=14490P = 14490
  • r=7.1%=0.071r = 7.1\% = 0.071
  • t=7t = 7 years

Let's calculate each case.


(a) Compounded Semiannually ( n=2n = 2 )

A=14490(1+0.0712)2Γ—7A = 14490 \left(1 + \frac{0.071}{2}\right)^{2 \times 7} A=14490(1+0.0355)14A = 14490 \left(1 + 0.0355\right)^{14} Aβ‰ˆ14490Γ—1.627A \approx 14490 \times 1.627 Aβ‰ˆ23558.23A \approx 23558.23

(b) Compounded Quarterly ( n=4n = 4 )

A=14490(1+0.0714)4Γ—7A = 14490 \left(1 + \frac{0.071}{4}\right)^{4 \times 7} A=14490(1+0.01775)28A = 14490 \left(1 + 0.01775\right)^{28} Aβ‰ˆ14490Γ—1.631A \approx 14490 \times 1.631 Aβ‰ˆ23617.59A \approx 23617.59

(c) Compounded Monthly ( n=12n = 12 )

A=14490(1+0.07112)12Γ—7A = 14490 \left(1 + \frac{0.071}{12}\right)^{12 \times 7} A=14490(1+0.0059167)84A = 14490 \left(1 + 0.0059167\right)^{84} Aβ‰ˆ14490Γ—1.634A \approx 14490 \times 1.634 Aβ‰ˆ23657.46A \approx 23657.46

(d) Compounded Continuously

A=14490β‹…e0.071β‹…7A = 14490 \cdot e^{0.071 \cdot 7} Aβ‰ˆ14490β‹…e0.497A \approx 14490 \cdot e^{0.497} Aβ‰ˆ14490Γ—1.644A \approx 14490 \times 1.644 Aβ‰ˆ23800.56A \approx 23800.56


Summary of Results

  • (a) Compounded Semiannually: $23,558.23
  • (b) Compounded Quarterly: $23,617.59
  • (c) Compounded Monthly: $23,657.46
  • (d) Compounded Continuously: $23,800.56

Would you like further details on any specific part?


Related Questions

  1. How does changing the compounding frequency impact the accumulated amount?
  2. What would be the accumulated value if the interest rate were 8% instead of 7.1%?
  3. How much more interest is earned with continuous compounding versus semiannual compounding?
  4. How would the accumulated amount change for an investment period of 10 years instead of 7?
  5. What would be the difference in the accumulated amount if the initial investment was $20,000 instead?

Tip:

The more frequently interest is compounded, the more interest is accumulated, but the differences diminish with very frequent compounding (like monthly to continuous).

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Continuous Compounding
Exponential Growth

Formulas

A = P(1 + r/n)^(nt)
A = Pe^(rt)

Theorems

Exponential Growth in Compound Interest

Suitable Grade Level

Grades 10-12