Math Problem Statement
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 2 cos(t) + sin(2t),
0, π 2
absolute minimum value
Correct: Your answer is correct. absolute maximum value
Solution
To find the absolute maximum and minimum values of the function on the interval , weβll follow these steps:
- Compute the derivative to find the critical points.
- Set and solve for within the interval.
- Evaluate at the critical points and endpoints and .
- Determine the maximum and minimum values from these evaluations.
Step 1: Compute the Derivative
The function is given by:
To differentiate, we use the derivatives of and :
Step 2: Set and Solve for
We need to find the values of that satisfy:
This simplifies to:
Using trigonometric identities, such as , this equation can be solved to find critical points within .
Step 3: Evaluate at Critical Points and Endpoints
Once we have critical points, we evaluate at these points as well as at and .
Step 4: Determine Maximum and Minimum Values
By comparing values from critical points and endpoints, we find the absolute maximum and absolute minimum values over the interval.
Would you like me to go further with specific critical points or evaluate the function with detailed calculations?
Here are related questions you might explore:
- How do critical points affect the outcome of maximum and minimum values?
- What is the importance of checking endpoints when finding absolute extrema?
- How does the derivative test help in finding extrema on closed intervals?
- What are alternative methods for verifying critical points in trigonometric functions?
- How does trigonometric identity simplification help in solving equations?
Tip: Always consider both endpoints and critical points within a given interval to ensure you have the absolute extrema for a function.
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Math Problem Analysis
Mathematical Concepts
Calculus
Trigonometric Functions
Optimization
Formulas
Derivative of f(t) to find critical points
Evaluating f(t) at critical points and endpoints
Theorems
Extreme Value Theorem
Suitable Grade Level
Grades 11-12, Calculus I level
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