Math Problem Statement
Solution
The task involves determining whether the given series converge absolutely, conditionally, or diverge. Let's analyze the two series one by one.
Problem (a):
Analysis:
-
Absolute Convergence:
To check for absolute convergence, consider the series of absolute values: The factorial grows extremely quickly, and we know that series of the form converge because the terms tend to zero extremely fast. Thus, this series converges absolutely. -
Conditional Convergence:
Since the series already converges absolutely, it automatically converges conditionally as well.
Problem (b):
Analysis:
-
Absolute Convergence:
Consider the series of absolute values: For large , the numerator behaves like (dominant term), and the denominator behaves like , so the terms simplify asymptotically to: Since grows without bound, the terms do not tend to zero, and the series diverges absolutely. -
Conditional Convergence:
Now consider the original alternating series. For alternating series to converge, the terms must:- Decrease monotonically ().
- Tend to zero ().
Since the absolute value of the terms grows like , they do not tend to zero. Therefore, the series does not converge conditionally either.
Final Results:
- (a): The series converges absolutely.
- (b): The series diverges.
Do you want a step-by-step explanation for any specific part? Let me know!
Related Questions:
- How does the factorial growth in series (a) ensure convergence?
- Why does the alternating series test fail in part (b)?
- Can series with terms tending to infinity ever converge conditionally?
- How can we test for divergence in non-alternating series?
- What are the differences between absolute and conditional convergence?
Tip:
When working with factorial-based terms, always compare their growth rate to standard tests (e.g., ratio test, comparison with ). This simplifies deciding convergence behavior.
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Math Problem Analysis
Mathematical Concepts
Series Convergence
Absolute Convergence
Conditional Convergence
Factorial Growth
Alternating Series
Formulas
|∑ (-1)^n / (3n-2)!|
|∑ n(3n^2 - 1) / (5 + 2n^2)|
Theorems
Absolute Convergence Test
Alternating Series Test
Suitable Grade Level
Undergraduate Level
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