Math Problem Statement

Question 3 options: An electrical company manufactures light bulbs that have a length of life that is normally distributed with standard deviation of 40 hours. If a sample of 30 bulbs has an average life of 780 hours, construct a 99% confidence interval for the population mean of all bulbs produced by this company. (Note: For all answers, just fill in the number.)

Sample size, n = 30 Sample mean, x ¯ (hours) = 780 Population standard deviation, σ (hours) = 40 Standard error (hours) (corr. to 3 dec. places) = Point estimate (hours) = Critical value, z* (corr. to 3 dec. places) = Margin of error (hours) (corr. to 2 dec. places) = We are 99% confident that (in hours) (both corr. to 1 dec. place):

Solution

To construct a 99% confidence interval for the population mean, we’ll calculate each part step-by-step.

Given values:

  • Sample size, n=30n = 30
  • Sample mean, xˉ=780\bar{x} = 780 hours
  • Population standard deviation, σ=40\sigma = 40 hours

Steps:

  1. Standard Error (SE): SE=σn=40307.302SE = \frac{\sigma}{\sqrt{n}} = \frac{40}{\sqrt{30}} \approx 7.302

  2. Point Estimate:

    • The point estimate for the population mean is simply the sample mean, so: Point Estimate=780 hours\text{Point Estimate} = 780 \text{ hours}
  3. Critical Value (z*) for 99% Confidence:

    • For a 99% confidence level, the critical value z\*z\* corresponds to 2.576 (from standard z-tables for a two-tailed test at 99% confidence).
    • Thus: z\*2.576z\* \approx 2.576
  4. Margin of Error (ME): ME=z\*×SE=2.576×7.30218.80ME = z\* \times SE = 2.576 \times 7.302 \approx 18.80

  5. Confidence Interval: Confidence Interval=xˉ±ME=780±18.80\text{Confidence Interval} = \bar{x} \pm ME = 780 \pm 18.80

    • Lower limit: 78018.80=761.2780 - 18.80 = 761.2
    • Upper limit: 780+18.80=798.8780 + 18.80 = 798.8

Summary of Answers:

  • Sample size, nn = 30
  • Sample mean, xˉ\bar{x} (hours) = 780
  • Population standard deviation, σ\sigma (hours) = 40
  • Standard error (hours) = 7.302 (correct to 3 decimal places)
  • Point estimate (hours) = 780
  • Critical value, z\*z\* = 2.576 (correct to 3 decimal places)
  • Margin of error (hours) = 18.80 (correct to 2 decimal places)
  • Confidence interval: We are 99% confident that the population mean is between 761.2 hours and 798.8 hours (both correct to 1 decimal place).

Would you like further details or have any questions about this calculation?

Further Related Questions:

  1. How would the confidence interval change with a 95% confidence level?
  2. What impact does increasing the sample size have on the confidence interval width?
  3. Why is the z-value used instead of the t-value in this calculation?
  4. How does the confidence interval change if the standard deviation increases?
  5. What would be the margin of error with a sample size of 50 bulbs?

Tip:

Confidence intervals provide a range within which we expect the true population mean to lie, given a certain level of confidence, offering insight into data reliability and precision.

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Math Problem Analysis

Mathematical Concepts

Statistics
Confidence Intervals
Normal Distribution

Formulas

Standard Error (SE) = σ / √n
Margin of Error (ME) = z* × SE
Confidence Interval = x̄ ± ME

Theorems

Central Limit Theorem
Properties of the Normal Distribution

Suitable Grade Level

Grades 11-12