Math Problem Statement
7 people visited a marriage function in 3 different vehicles each accomodating max of 5 ppl how many ways can they visit such that they use all 3 vehicles
Solution
We are asked to find how many ways 7 people can visit a marriage function using 3 vehicles, each with a capacity of 5 people, such that all 3 vehicles are used.
Step 1: Partitioning the 7 people into 3 groups
We need to split 7 people into 3 groups such that none of the groups is empty (since all 3 vehicles must be used). The groups can have the following distribution:
- One group with 3 people, one group with 2 people, and one group with 2 people.
Step 2: Counting the number of ways to partition the people
We calculate the number of ways to assign people to these groups.
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Choose 3 people for the first group: There are ways to choose 3 people.
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Choose 2 people for the second group: After choosing 3 people for the first group, we are left with 4 people. There are ways to choose 2 people for the second group.
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The remaining 2 people automatically go to the third group: There's only 1 way to assign these last 2 people.
Step 3: Considering the arrangement of vehicles
Since the vehicles are distinct, the arrangement of the groups into the vehicles matters. There are 3! (factorial) ways to assign the 3 groups to the 3 vehicles:
Step 4: Final calculation
Now, multiply all the factors together:
Thus, the total number of ways the 7 people can visit using all 3 vehicles is 1260.
Would you like more details on any of the steps?
Related Questions:
- How do you calculate the binomial coefficient ?
- What is the principle behind arranging groups into distinct sets?
- How would the answer change if one vehicle could hold only 3 people?
- Can you solve similar problems where some vehicles have larger capacities?
- How does Stirling’s formula approximate these types of combinatorial problems?
Tip:
When solving combinatorics problems, breaking the task into smaller, manageable steps—like grouping and arranging—is key to avoiding mistakes!
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Math Problem Analysis
Mathematical Concepts
Combinatorics
Permutations
Combinations
Factorials
Formulas
Binomial Coefficient: \(\binom{n}{r} = \frac{n!}{r!(n - r)!}\)
Factorial: \(n! = n \times (n-1) \times ... \times 1\)
Theorems
Basic Permutation and Combination Theorems
Suitable Grade Level
Grades 9-12
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