Math Problem Statement

Sketch a 3-input NAND gate with transistor widths chosen to achieve effective rise and fall resistances equal to a unit inverter (R). Estimate worst-case rising and falling delay of 3- input NAND driving h identical gates.

Solution

Step 1: Sketching the 3-input NAND Gate with Transistor Widths

A 3-input NAND gate has three NMOS transistors in series and three PMOS transistors in parallel. To match the effective rise and fall resistances with that of a unit inverter, we need to adjust the transistor widths.

  • NMOS Network: In a NAND gate, the NMOS transistors are in series. For three transistors in series, the resistance would add up. To achieve the same resistance RR as a unit inverter, each NMOS transistor's width WnW_n should be increased by a factor of 3. Hence, Wn,NAND=3WnW_{n, \text{NAND}} = 3W_n.

  • PMOS Network: In a NAND gate, the PMOS transistors are in parallel. To achieve the same resistance RR, each PMOS transistor's width WpW_p can be kept the same as in the unit inverter because parallel transistors reduce the effective resistance. Hence, Wp,NAND=WpW_{p, \text{NAND}} = W_p.

Step 2: Estimating the Worst-Case Rising and Falling Delay

Worst-Case Falling Delay:

  • Falling Delay is dominated by the NMOS transistors, which are in series.

  • With three NMOS transistors in series, the effective resistance is approximately RR.

  • The load capacitance is h×CLh \times C_L (where CLC_L is the load capacitance of one gate, and hh is the number of identical gates driven).

  • The worst-case falling delay tft_f is given by:

    tf=R×hCLt_f = R \times hC_L

Worst-Case Rising Delay:

  • Rising Delay is dominated by the PMOS transistors, which are in parallel.

  • Even though the PMOS transistors are in parallel, only one of them will be active during the worst-case scenario, making the effective resistance RR.

  • The load capacitance remains h×CLh \times C_L.

  • The worst-case rising delay trt_r is given by:

    tr=R×hCLt_r = R \times hC_L

Summary:

  • The transistor widths for the 3-input NAND gate:
    • Wn,NAND=3WnW_{n, \text{NAND}} = 3W_n (for NMOS)
    • Wp,NAND=WpW_{p, \text{NAND}} = W_p (for PMOS)
  • The worst-case rising and falling delays are both estimated to be: tftrR×hCLt_f \approx t_r \approx R \times hC_L

This indicates that the worst-case delay is linearly proportional to the number of identical gates hh being driven.

Would you like more details on any step, or do you have any further questions?


Here are some additional questions for further exploration:

  1. What are the effects of increasing the transistor width on power consumption?
  2. How would you modify the design if the load is not identical gates but a capacitive load?
  3. What is the impact of threshold voltage on the delay of the NAND gate?
  4. How does the delay of a NAND gate compare to that of a NOR gate for the same transistor sizes?
  5. What role does body effect play in the performance of a NAND gate?

Tip: In CMOS design, balancing power consumption and speed is crucial. Increasing transistor width reduces delay but increases dynamic power due to larger charging and discharging currents.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

CMOS Logic
Transistor Sizing
Digital Circuit Delay

Formulas

Worst-case falling delay: tf = R × hCL
Worst-case rising delay: tr = R × hCL
NMOS Transistor Width: Wn_NAND = 3Wn
PMOS Transistor Width: Wp_NAND = Wp

Theorems

Ohm's Law in Resistance Calculation
Capacitance Load and Delay in Digital Circuits

Suitable Grade Level

Undergraduate - Electrical Engineering