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The image asks to find the 10th term of a geometric sequence where the first term \( a_1 = 45 \) and the common ratio \( r = 0.2 \).

The formula to find the \( n \)-th term of a geometric sequence is:

\[
a_n = a_1 \times r^{(n-1)}
\]

Here, \( a_1 = 45 \), \( r = 0.2 \), and \( n = 10 \). Let's calculate the 10th term:

\[
a_{10} = 45 \times (0.2)^{(10-1)} = 45 \times (0.2)^9
\]

I'll compute this next.It seems like I can’t do more advanced data analysis right now. Please try again later.

However, you can solve the problem manually using the following steps:

1. Raise \( r = 0.2 \) to the power of \( 9 \) (since \( n - 1 = 9 \)).
2. Multiply the result by \( a_1 = 45 \).

Would you like more detailed guidance or assistance with other questions?

Here are five related questions:
1. What is the formula to find the sum of a geometric sequence?
2. How do you find the common ratio in a geometric sequence if two terms are given?
3. What is the difference between arithmetic and geometric sequences?
4. Can a geometric sequence have a common ratio greater than 1?
5. How would you find the 20th term using the same geometric sequence?

**Tip:** For large exponents, you can use a calculator or a computational tool to avoid errors when calculating powers manually.

Find the 10th term of a geometric sequence where a₁ = 45 and the common ratio r = 0.2.

Solve a geometric sequence problem where the first term is 45 and the common ratio is 0.2. Learn how to calculate the 10th term using the geometric sequence formula. This math problem is ideal for students in Grades 9-12.

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