Let's tackle this problem step by step. Here's how we can approach each part:

Given Information:

• Load (W) = 2 kg
• Length of the wire (L) = 5 m = 5000 mm
• Elongation (ΔL) = 0.25 mm
• Radius of the wire (r) = 1 mm
• Acceleration due to gravity (g) = 9.8 m/s² (to calculate the force from the weight)

We can now break down the problem into its components:

1. Reflexive Power

Reflexive power is not a common physical term in the context of material mechanics, elasticity, or wire tension. It's possible this is a misinterpretation or unrelated to this type of problem. If you meant something else, please clarify.

2. Strain

Strain is a measure of deformation of the material. It is given by the ratio of change in length (elongation) to the original length.

$\text{Strain} = \frac{\Delta L}{L}$

Substituting the values:

$\text{Strain} = \frac{0.25}{5000} = 0.00005$

So, the strain in the wire is 0.00005.

3. Young's Modulus (E)

Young's modulus is a measure of the stiffness of a material. It is calculated using the formula:

$E = \frac{\text{Stress}}{\text{Strain}}$

Stress is the force applied per unit area. To calculate the force:

$\text{Force} = \text{Weight} = m \cdot g = 2 \cdot 9.8 = 19.6 \, \text{N}$

The cross-sectional area of the wire is given by:

$A = \pi r^2 = \pi (1 \, \text{mm})^2 = \pi \, \text{mm}^2 = 3.14 \, \text{mm}^2 = 3.14 \times 10^{-6} \, \text{m}^2$

Now, Stress is the force divided by the cross-sectional area:

$\text{Stress} = \frac{\text{Force}}{A} = \frac{19.6}{3.14 \times 10^{-6}} = 6.24 \times 10^6 \, \text{Pa}$

Finally, the Young's Modulus (E) is:

$E = \frac{6.24 \times 10^6}{0.00005} = 1.248 \times 10^{11} \, \text{Pa}$

Thus, the Young's modulus of the material is approximately $1.25 \times 10^{11} \, \text{Pa}$.

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Summary of Results:

• Strain: 0.00005
• Young's Modulus: $1.25 \times 10^{11} \, \text{Pa}$

Would you like more details on any of these calculations?

5 Related Questions:

1. What is the physical significance of Young's modulus in material science?
2. How would the strain change if the load were doubled?
3. What happens to the wire if the Young's modulus is lower than calculated?
4. How is stress different from pressure in mechanical terms?
5. How would the elongation change if the radius of the wire was halved?

Tip:

Young's modulus is a fundamental property that indicates how easily a material deforms under tension. High values mean the material is stiffer and more resistant to deformation.