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The problem in the image describes a situation where the work \( W \) (in joules) done when lifting an object varies jointly with the mass \( m \) (in kilograms) of the object and the height \( h \) (in meters) that the object is lifted. This suggests a formula of the form:

\[
W = k \cdot m \cdot h
\]

Where \( k \) is the constant of proportionality.

### Given:
- When a 100-kg object is lifted to a height of 1.5 meters, the work done is 1470 Joules.
  \[
  W = 1470 \, \text{J}, \, m = 100 \, \text{kg}, \, h = 1.5 \, \text{m}
  \]

#### Step 1: Find \( k \)

We can use the formula \( W = k \cdot m \cdot h \) to solve for \( k \).

\[
1470 = k \cdot 100 \cdot 1.5
\]

\[
k = \frac{1470}{100 \cdot 1.5} = \frac{1470}{150} = 9.8
\]

So, \( k = 9.8 \).

#### Step 2: Calculate the work done for a 150-kg object lifted 2 meters.

Now that we know \( k = 9.8 \), we can use the formula again to calculate the work:

\[
W = 9.8 \cdot 150 \cdot 2
\]

\[
W = 9.8 \cdot 300 = 2940 \, \text{Joules}
\]

### Final Answer:
The work done when lifting a 150-kg object to a height of 2 meters is 2940 Joules.

Do you need more details or have any questions?

Here are 5 related questions:
1. How does the proportionality constant \( k \) relate to gravitational force?
2. What are the units for work, and how are they derived from mass and height?
3. How would the work change if the height were doubled while keeping the mass constant?
4. Can this formula apply to any object being lifted on Earth?
5. How would you calculate the power if the object is lifted in 3 seconds?

**Tip:** Joint variation means that the work depends on the product of both mass and height, which means increasing either one will linearly increase the work done.

The work (in Joules) done when lifting an object varies jointly with the mass (in kilograms) of the object and the height (in meters) that the object is lifted. The work done when a 100-kilogram object is lifted 1.5 meters is 1470 Joules. How much work is done when lifting a 150-kilogram object 2 meters?

Solve how much work is done when lifting a 150kg object to a height of 2 meters, using the formula for joint variation. Learn how mass and height impact the energy required for lifting objects.

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