Math Problem Statement
A force of 3 pounds compresses a 15 inch spring a total of 3 inches. How much work (in ft-lbs) is done in compressing the spring 10 inches?
Solution
To solve this problem, we need to use Hooke's Law for springs and the work done to compress a spring. Hooke's Law states that the force required to compress or extend a spring is proportional to the displacement from its natural length:
Where:
- is the force applied,
- is the spring constant (stiffness),
- is the displacement (amount the spring is compressed or stretched).
Step 1: Find the Spring Constant
We are given:
- A force pounds,
- A compression distance inches.
Using Hooke’s Law:
Solving for :
Step 2: Set Up the Work Formula
The work done on a spring is given by the formula:
Where:
- is the work done,
- is the final displacement.
For a spring with spring constant , the work to compress it from to is:
Step 3: Calculate the Work for a 10-Inch Compression
We are asked to find the work required to compress the spring by 10 inches. Using the work formula:
Step 4: Convert Inch-Pounds to Foot-Pounds
Since there are 12 inches in a foot, we convert 50 inch-pounds to foot-pounds:
Thus, the work done in compressing the spring by 10 inches is approximately 4.17 foot-pounds.
Would you like more details on any part of the solution or have any further questions?
Related Questions:
- What is Hooke’s Law, and how is it applied in real-world examples?
- How does the spring constant affect the amount of work done in compressing or stretching a spring?
- What is the formula for the potential energy stored in a compressed spring?
- How do you convert between different units of work, such as inch-pounds and foot-pounds?
- What is the relationship between force and displacement for non-linear systems?
Tip: Always ensure unit consistency, especially when switching between systems like inches to feet!
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Math Problem Analysis
Mathematical Concepts
Physics
Hooke's Law
Work-Energy Principle
Formulas
Hooke's Law: F = kx
Work Formula for Springs: W = (1/2)kx^2
Unit Conversion: 1 foot = 12 inches
Theorems
Hooke's Law
Work-Energy Theorem
Suitable Grade Level
Grades 10-12