Math Problem Statement

suppose a windmill generates power based on the speed of the wind. Thua is represented by the polynomial function P(s)= S⁴ divide 1000, where s represented the speed of the wind in kilometers per hour. If the wind speed is 15 kilometers per hour, how many units of power, P(s) can the windmill generate?

Solution

To solve for the power generated by the windmill when the wind speed is 15 kilometers per hour, we use the polynomial function provided:

P(s)=s41000P(s) = \frac{s^4}{1000}

Where ss is the wind speed in kilometers per hour. Substituting s=15s = 15 into the equation:

P(15)=1541000P(15) = \frac{15^4}{1000}

First, calculate 15415^4:

154=15×15×15×15=5062515^4 = 15 \times 15 \times 15 \times 15 = 50625

Now, divide by 1000:

P(15)=506251000=50.625P(15) = \frac{50625}{1000} = 50.625

Therefore, the windmill generates 50.625 units of power when the wind speed is 15 kilometers per hour.

Would you like further details or have any questions?

Related Questions:

  1. How does power generation change if the wind speed is doubled?
  2. What is the power output when the wind speed is 20 km/h?
  3. How would the formula change if we wanted to model power based on the square of wind speed instead of the fourth power?
  4. What happens to the power output if the wind speed is halved?
  5. Can you calculate the speed needed to generate 100 units of power?

Tip: Wind power generation typically increases with the cube of wind speed in real-world models, but higher powers like s4s^4 can also be used to emphasize sensitivity in specific contexts.

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Functions
Exponents

Formulas

P(s) = s⁴ / 1000

Theorems

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Suitable Grade Level

Grades 9-12