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The problem presents the following information:

- The dealer buys 11 kg of wheat at Rs. 275 per kg.
- He mixes this with another quality of wheat in the ratio of 4:5.
- The price of the resulting mixture is Rs. 30 per kg.
- We are asked to find the price of the other quality of wheat.

We can solve this using the concept of weighted averages. Let the price of the other quality of wheat be \( x \) (Rs. per kg). Using the given ratio of 4:5, we can form an equation based on the average price of the mixture.

### Step-by-step solution:

1. Let the quantities of the two types of wheat in the mixture be:
   - First type (at Rs. 275 per kg): \( 4 \) parts.
   - Second type (at \( x \) Rs. per kg): \( 5 \) parts.

2. The total price per kg of the mixture is Rs. 30.

3. We use the formula for the weighted average price:
   \[
   \text{Weighted average price} = \frac{(4 \times 275) + (5 \times x)}{4 + 5}
   \]
   Substituting the value of the mixture price (Rs. 30 per kg):
   \[
   30 = \frac{(4 \times 275) + (5 \times x)}{9}
   \]

4. Simplify the equation:
   \[
   30 \times 9 = 4 \times 275 + 5 \times x
   \]
   \[
   270 = 1100 + 5x
   \]

5. Solve for \( x \):
   \[
   5x = 270 - 1100
   \]
   \[
   5x = -830
   \]
   \[
   x = \frac{-830}{5}
   \]
   \[
   x = -166
   \]

### Conclusion:
The price of the other quality of wheat is Rs. **-166** per kg. However, this negative price may indicate an issue with the given data or assumptions in the problem, as a price cannot be negative.

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A dealer buys 11 kg of wheat at Rs. 275 and mixes it with another quality of wheat in the ratio of 4:5. The price of the resulting mixture is Rs. 30 per kg. The price of this other quality of wheat is?

Learn how to solve a wheat price mixture problem where a dealer buys two types of wheat in a ratio of 4:5. Using weighted averages, determine the price of the second type of wheat, given that the price of the mixture is Rs. 30 per kg. Suitable for students in Grades 8-10.

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