Math Problem Statement

Consider the weighted voting system [q: 9, 5, 1]. What is the smallest value for q that results in exactly two players with veto power? Here is an example of a similiar problem: In the weighted voting system [q: 5, 4, 3, 1], for which values of q does P1 have veto power? Answer: 9, 10, 11, 12, 13. Explanation : Together, P2, P3, and P4 have 8 votes. If they all vote Yea, they can pass a resolution without P1 as long as q is no more than 8. Otherwise, P1 has veto power.

Solution

In a weighted voting system like [q:9,5,1][q: 9, 5, 1], qq is the quota (the number of votes required to pass a resolution), and the numbers represent the voting weights of the players, i.e., Player 1 (P1) has 9 votes, Player 2 (P2) has 5 votes, and Player 3 (P3) has 1 vote.

We need to determine the smallest value of qq that results in exactly two players having veto power.

Definition of Veto Power:

A player has veto power if their vote is necessary to reach or exceed the quota qq. In other words, a player has veto power if the other players combined cannot reach the quota without that player's votes.

Step-by-Step Process:

Step 1: Determine total votes.

The total number of votes in the system is: 9+5+1=15 votes.9 + 5 + 1 = 15 \text{ votes}.

Step 2: Consider cases for veto power.

  • Player 1 (P1) has 9 votes.
  • Player 2 (P2) has 5 votes.
  • Player 3 (P3) has 1 vote.

We need to identify the smallest value of qq such that exactly two players (P1 and P2) have veto power.

Step 3: Find the conditions for veto power.

  • P1 has veto power if the other two players (P2 and P3) together cannot reach qq. This means that P2 and P3 together have 5 + 1 = 6 votes, so if q>6q > 6, P1 will have veto power.
  • P2 has veto power if P1 and P3 together cannot reach qq. Since P1 and P3 together have 9 + 1 = 10 votes, P2 will have veto power if q>10q > 10.

For exactly two players to have veto power, both P1 and P2 must have veto power, while P3 does not.

Step 4: Smallest qq value.

For P3 not to have veto power, P1 and P2 must be able to pass a resolution without P3. That is, q9+5=14q \leq 9 + 5 = 14.

Thus, the smallest qq must satisfy:

  • q>6q > 6 (so that P1 has veto power),
  • q>10q > 10 (so that P2 has veto power),
  • q14q \leq 14 (so that P3 does not have veto power).

The smallest such qq is 11.

Conclusion:

The smallest value of qq that results in exactly two players (P1 and P2) having veto power is 11.


Would you like further details or have any questions?

Here are 5 related questions to deepen your understanding:

  1. For which values of qq does P1 alone have veto power in the system [q:9,5,1][q: 9, 5, 1]?
  2. What happens if q=7q = 7? Who has veto power?
  3. How does changing P3's vote from 1 to 2 affect the veto power in this system?
  4. What is the total number of winning coalitions if q=11q = 11?
  5. How do weighted voting systems model real-world decision-making?

Tip: In weighted voting, veto power is crucial in determining which players are essential to form a coalition that can pass decisions. Adjusting the quota affects the power distribution significantly.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Weighted Voting Systems
Veto Power
Coalition Formation

Formulas

Total votes = sum of all player votes
Veto power condition: If a player's vote is necessary to reach the quota q, that player has veto power.

Theorems

Veto Power Theorem: A player has veto power if the remaining players' combined votes are insufficient to reach or exceed the quota.

Suitable Grade Level

Grades 10-12