Math Problem Statement
Consider the weighted voting system [q: 9, 5, 1]. What is the smallest value for q that results in exactly two players with veto power? Here is an example of a similiar problem: In the weighted voting system [q: 5, 4, 3, 1], for which values of q does P1 have veto power? Answer: 9, 10, 11, 12, 13. Explanation : Together, P2, P3, and P4 have 8 votes. If they all vote Yea, they can pass a resolution without P1 as long as q is no more than 8. Otherwise, P1 has veto power.
Solution
In a weighted voting system like , is the quota (the number of votes required to pass a resolution), and the numbers represent the voting weights of the players, i.e., Player 1 (P1) has 9 votes, Player 2 (P2) has 5 votes, and Player 3 (P3) has 1 vote.
We need to determine the smallest value of that results in exactly two players having veto power.
Definition of Veto Power:
A player has veto power if their vote is necessary to reach or exceed the quota . In other words, a player has veto power if the other players combined cannot reach the quota without that player's votes.
Step-by-Step Process:
Step 1: Determine total votes.
The total number of votes in the system is:
Step 2: Consider cases for veto power.
- Player 1 (P1) has 9 votes.
- Player 2 (P2) has 5 votes.
- Player 3 (P3) has 1 vote.
We need to identify the smallest value of such that exactly two players (P1 and P2) have veto power.
Step 3: Find the conditions for veto power.
- P1 has veto power if the other two players (P2 and P3) together cannot reach . This means that P2 and P3 together have 5 + 1 = 6 votes, so if , P1 will have veto power.
- P2 has veto power if P1 and P3 together cannot reach . Since P1 and P3 together have 9 + 1 = 10 votes, P2 will have veto power if .
For exactly two players to have veto power, both P1 and P2 must have veto power, while P3 does not.
Step 4: Smallest value.
For P3 not to have veto power, P1 and P2 must be able to pass a resolution without P3. That is, .
Thus, the smallest must satisfy:
- (so that P1 has veto power),
- (so that P2 has veto power),
- (so that P3 does not have veto power).
The smallest such is 11.
Conclusion:
The smallest value of that results in exactly two players (P1 and P2) having veto power is 11.
Would you like further details or have any questions?
Here are 5 related questions to deepen your understanding:
- For which values of does P1 alone have veto power in the system ?
- What happens if ? Who has veto power?
- How does changing P3's vote from 1 to 2 affect the veto power in this system?
- What is the total number of winning coalitions if ?
- How do weighted voting systems model real-world decision-making?
Tip: In weighted voting, veto power is crucial in determining which players are essential to form a coalition that can pass decisions. Adjusting the quota affects the power distribution significantly.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Weighted Voting Systems
Veto Power
Coalition Formation
Formulas
Total votes = sum of all player votes
Veto power condition: If a player's vote is necessary to reach the quota q, that player has veto power.
Theorems
Veto Power Theorem: A player has veto power if the remaining players' combined votes are insufficient to reach or exceed the quota.
Suitable Grade Level
Grades 10-12
Related Recommendation
Weighted Voting System with Quota 47 and Total 9 Players
Weighted Voting System [65 : 30, 28, 22, 15, 7, 6]: Players, Quota, and Weights
Banzhaf Power Distribution for Weighted Voting System [50, 40, 30, 20, 10] with Quotas 100, 106, 112, 149
Calculate Banzhaf Power Distribution for Weighted Voting System with q=107
Banzhaf Power Distribution for Weighted Voting System with Quotas 20, 21, 24, 29