Math Problem Statement

A swimming pool is 20 ft wide, 40 ft long, 3 ft deep at the shallow end, and 9 feet deep at its deepest point. A cross-section is shown in the figure. (a) Express the volume of the water in the pool as a function of height h of the water above the deepest point. (b) Determine the domain and range of the function found in part (a).

Solution

Problem Breakdown:

We are given a swimming pool with the following dimensions:

  • Width: 20 feet
  • Length: 40 feet
  • Depth: 3 feet at the shallow end and 9 feet at the deep end.
  • The cross-section is shown as a trapezoid from the shallow to deep end.

The goal is to:

  1. Express the volume of the pool as a piecewise function of the height hh of the water above the deepest point (9 feet).
  2. Determine the domain and range of this piecewise function.

Step 1: Understanding the Geometry

We can divide the pool into two sections:

  • Region 1: From x=0x = 0 to x=12x = 12, where the pool's depth linearly increases from 3 ft to 9 ft (sloped region).
  • Region 2: From x=12x = 12 to x=40x = 40, where the pool is uniformly 9 ft deep.

The volume as a function of hh depends on how high the water level is relative to the deepest point.

Step 2: Volume in Region 1 (Sloped section)

In this region, the depth increases linearly from 3 ft to 9 ft. Let’s derive the depth at any point along the slope.

  • The equation of the line from the shallow end to the deep end is given by: d(x)=612x+3=0.5x+3d(x) = \frac{6}{12}x + 3 = 0.5x + 3 where d(x)d(x) is the depth at any point xx from 0 to 12 ft.

  • Now, for a given height hh, the volume of water in this region will be the area of a trapezoid cross-section multiplied by the width (20 ft) and length (12 ft). This is for hh values less than or equal to 6 ft, because this region ends at a depth of 9 ft.

Step 3: Volume in Region 2 (Constant depth section)

For h>6h > 6, the water height in this region covers the constant depth part, where the depth is 9 ft throughout. For this section, the volume calculation is straightforward since the depth remains constant at 9 ft.


Let me work out the exact piecewise formula for the volume and determine the domain and range.It seems like I can’t do more advanced data analysis right now. Please try again later.

However, I can outline the process for you manually if you'd like.

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Math Problem Analysis

Mathematical Concepts

Geometry
Piecewise Functions
Volume Calculation

Formulas

Volume of a trapezoidal prism: V = (1/2) * (a + b) * h * l
Linear equation for sloped region depth: d(x) = 0.5x + 3

Theorems

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Suitable Grade Level

Grades 9-12