Math Problem Statement

Find the volume of the solid with the given base and cross-sections by first finding the formula for the area of a typical cross-section and then integrating over the appropriate region and variable. The base of the region is enclosed by y = 5 - x^2 and y = 2, and the cross-sections perpendicular to the y-axis are squares.

Solution

We are asked to find the volume of a solid with a given base and square cross-sections. Let's go through the solution process step by step.

Problem Summary:

We are given:

  • The base of the region is enclosed by y=5x2y = 5 - x^2 and y=2y = 2.
  • The cross-sections perpendicular to the yy-axis are squares.

We need to:

  1. Find the formula for the area of a typical cross-section (which is a square).
  2. Set up and evaluate the integral to find the volume.

Step 1: Identify the bounds for xx

The cross-sections are perpendicular to the yy-axis, so we express xx in terms of yy. For the base, the curve y=5x2y = 5 - x^2 can be rewritten as: x2=5yorx=±5yx^2 = 5 - y \quad \text{or} \quad x = \pm \sqrt{5 - y} Thus, the width of the square cross-section at a given yy will be 25y2\sqrt{5 - y}.

Step 2: Find the area of a typical cross-section

Since the cross-section is a square, the side length of the square at a given yy is 25y2\sqrt{5 - y}. The area of the square is: Area=(25y)2=4(5y)=204y\text{Area} = \left( 2\sqrt{5 - y} \right)^2 = 4(5 - y) = 20 - 4y

Step 3: Set up the integral

The volume of the solid can be found by integrating the area of the cross-sections along the yy-axis from y=2y = 2 to y=5y = 5, as these are the bounds of the base. Therefore, the volume VV is: V=25(204y)dyV = \int_{2}^{5} (20 - 4y) \, dy

Step 4: Evaluate the integral

Now we compute the integral: V=25(204y)dy=[20y2y2]25V = \int_{2}^{5} (20 - 4y) \, dy = \left[ 20y - 2y^2 \right]_{2}^{5} Evaluating this: V=(20(5)2(5)2)(20(2)2(2)2)V = \left( 20(5) - 2(5)^2 \right) - \left( 20(2) - 2(2)^2 \right) V=(10050)(408)=5032=18V = (100 - 50) - (40 - 8) = 50 - 32 = 18

Final Answer:

The volume of the solid is 1818 cubic units.


Would you like more details or have any questions about this process?

Here are 5 related questions to deepen your understanding:

  1. How would the volume change if the cross-sections were rectangles instead of squares?
  2. What if the cross-sections were semicircles instead of squares?
  3. How would the integral change if the base was enclosed by different curves, such as y=3x2y = 3 - x^2?
  4. How can you find the volume if the cross-sections were not perpendicular to the yy-axis but to the xx-axis?
  5. What methods could you use to approximate the volume if the function was more complex?

Tip: When dealing with solids of revolution or other shapes, always start by analyzing the shape of the cross-section and relate it to the variable of integration.

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Geometry of Solids
Cross-sectional Areas

Formulas

Area of a square cross-section: A = (2√(5 - y))^2 = 4(5 - y) = 20 - 4y
Volume of solid: V = ∫ from y=2 to y=5 (20 - 4y) dy

Theorems

Fundamental Theorem of Calculus

Suitable Grade Level

Grades 11-12 (or early college level)