Math Problem Statement
Solution
We are asked to find the volume of a solid with a given base and square cross-sections. Let's go through the solution process step by step.
Problem Summary:
We are given:
- The base of the region is enclosed by and .
- The cross-sections perpendicular to the -axis are squares.
We need to:
- Find the formula for the area of a typical cross-section (which is a square).
- Set up and evaluate the integral to find the volume.
Step 1: Identify the bounds for
The cross-sections are perpendicular to the -axis, so we express in terms of . For the base, the curve can be rewritten as: Thus, the width of the square cross-section at a given will be .
Step 2: Find the area of a typical cross-section
Since the cross-section is a square, the side length of the square at a given is . The area of the square is:
Step 3: Set up the integral
The volume of the solid can be found by integrating the area of the cross-sections along the -axis from to , as these are the bounds of the base. Therefore, the volume is:
Step 4: Evaluate the integral
Now we compute the integral: Evaluating this:
Final Answer:
The volume of the solid is cubic units.
Would you like more details or have any questions about this process?
Here are 5 related questions to deepen your understanding:
- How would the volume change if the cross-sections were rectangles instead of squares?
- What if the cross-sections were semicircles instead of squares?
- How would the integral change if the base was enclosed by different curves, such as ?
- How can you find the volume if the cross-sections were not perpendicular to the -axis but to the -axis?
- What methods could you use to approximate the volume if the function was more complex?
Tip: When dealing with solids of revolution or other shapes, always start by analyzing the shape of the cross-section and relate it to the variable of integration.
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Math Problem Analysis
Mathematical Concepts
Integral Calculus
Geometry of Solids
Cross-sectional Areas
Formulas
Area of a square cross-section: A = (2√(5 - y))^2 = 4(5 - y) = 20 - 4y
Volume of solid: V = ∫ from y=2 to y=5 (20 - 4y) dy
Theorems
Fundamental Theorem of Calculus
Suitable Grade Level
Grades 11-12 (or early college level)
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