Math Problem Statement

Find the volume of the solid of revolution obtained by rotating the region bounded by y=√x, y=1/x and x=4 about the y -axis. Answer:

Solution

To find the volume of the solid of revolution obtained by rotating the given region about the yy-axis, we use the method of cylindrical shells or the washer method. Here, the washer method is appropriate.

Step 1: Analyze the bounds

  • The region is bounded by:
    1. y=xy = \sqrt{x}
    2. y=1xy = \frac{1}{x}
    3. x=4x = 4

We rewrite these in terms of xx to express xx as a function of yy:

  • y=x    x=y2y = \sqrt{x} \implies x = y^2
  • y=1x    x=1yy = \frac{1}{x} \implies x = \frac{1}{y}

For yy-bounds:

  • At x=4x = 4, y=4=2y = \sqrt{4} = 2 for y=xy = \sqrt{x}, and y=14y = \frac{1}{4} for y=1xy = \frac{1}{x}.
  • So, the bounds of integration are y[14,2]y \in \left[\frac{1}{4}, 2\right].

Step 2: Set up the volume integral

The volume is given by the formula for solids of revolution about the yy-axis:

V=πyminymax[Outer radius2Inner radius2]dyV = \pi \int_{y_{\text{min}}}^{y_{\text{max}}} \left[\text{Outer radius}^2 - \text{Inner radius}^2\right] \, dy

  • The outer radius is given by x=4x = 4 (fixed vertical line).
  • The inner radius is the xx-coordinate of the curve y=1xy = \frac{1}{x}, rewritten as x=1yx = \frac{1}{y}.

Thus, the volume integral becomes: V=π142[42(1y)2]dyV = \pi \int_{\frac{1}{4}}^{2} \left[4^2 - \left(\frac{1}{y}\right)^2\right] \, dy

Step 3: Simplify and compute the integral

V=π142[161y2]dyV = \pi \int_{\frac{1}{4}}^{2} \left[16 - \frac{1}{y^2}\right] \, dy

Separate the integral: V=π[14216dy1421y2dy]V = \pi \left[ \int_{\frac{1}{4}}^{2} 16 \, dy - \int_{\frac{1}{4}}^{2} \frac{1}{y^2} \, dy \right]

First integral:

14216dy=16[y]142=16(214)=1674=28\int_{\frac{1}{4}}^{2} 16 \, dy = 16 \left[y\right]_{\frac{1}{4}}^{2} = 16 \left(2 - \frac{1}{4}\right) = 16 \cdot \frac{7}{4} = 28

Second integral:

1421y2dy=[1y]142=12(4)=12+4=72\int_{\frac{1}{4}}^{2} \frac{1}{y^2} \, dy = \left[-\frac{1}{y}\right]_{\frac{1}{4}}^{2} = -\frac{1}{2} - \left(-4\right) = -\frac{1}{2} + 4 = \frac{7}{2}

Step 4: Combine results

V=π[2872]=π5672=π492=49π2V = \pi \left[28 - \frac{7}{2}\right] = \pi \cdot \frac{56 - 7}{2} = \pi \cdot \frac{49}{2} = \frac{49\pi}{2}

Final Answer:

49π2\boxed{\frac{49\pi}{2}}

Would you like further details or another example? Here are 5 related questions you might find helpful:

  1. How do we find the volume of solids using the disk method?
  2. How does the cylindrical shell method compare to the washer method for this problem?
  3. Can this integral be solved numerically instead of analytically?
  4. How does the volume change if the rotation is around the xx-axis?
  5. What happens if the boundary x=4x = 4 is replaced with another value?

Tip: Always visualize the region and axis of rotation to ensure correct setup of integrals.

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Math Problem Analysis

Mathematical Concepts

Volume of solids of revolution
Definite integration
Washer method

Formulas

V = π ∫[y_min, y_max] (Outer radius^2 - Inner radius^2) dy
y = √x implies x = y^2
y = 1/x implies x = 1/y

Theorems

Fundamental Theorem of Calculus

Suitable Grade Level

Grades 11-12