Express the volume of the solid enclosed by the paraboloids y=2x2+2z2
 and y=80−3x2−3z2
 with a triple integral.

Given the region of integration which would be the easiest order of integration?
Check all that apply.

To express the volume of the solid enclosed by the paraboloids \( y = 2x^2 + 2z^2 \) and \( y = 80 - 3x^2 - 3z^2 \), we first need to set up the triple integral for this region.

### Step 1: Find the Bounds
1. **Intersection of Paraboloids**: Set \( y = 2x^2 + 2z^2 \) equal to \( y = 80 - 3x^2 - 3z^2 \):
   \[
   2x^2 + 2z^2 = 80 - 3x^2 - 3z^2
   \]
   Simplifying this equation:
   \[
   5x^2 + 5z^2 = 80 \Rightarrow x^2 + z^2 = 16
   \]
   This implies that the projection of the region onto the \( xz \)-plane is a circle of radius 4 (since \( x^2 + z^2 \leq 16 \)).

2. **Volume Integral**: The volume of the region can be represented by the triple integral
   \[
   V = \iiint\limits_{\text{region}} 1 \, dV
   \]
   where the region is bounded by \( y = 2x^2 + 2z^2 \) from below and \( y = 80 - 3x^2 - 3z^2 \) from above.

### Step 2: Set up the Integral
We can set up the triple integral as follows:

\[
V = \int_{x=-4}^{4} \int_{z=-\sqrt{16 - x^2}}^{\sqrt{16 - x^2}} \int_{y = 2x^2 + 2z^2}^{80 - 3x^2 - 3z^2} 1 \, dy \, dz \, dx
\]

### Choosing the Easiest Order of Integration
Given the symmetry in the \( x \)- and \( z \)-variables (as indicated by \( x^2 + z^2 \leq 16 \)), it would be beneficial to switch to cylindrical coordinates for easier integration.

In cylindrical coordinates:
- Let \( x = r \cos \theta \) and \( z = r \sin \theta \),
- The bounds become \( r \in [0, 4] \), \( \theta \in [0, 2\pi] \),
- \( y \)-bounds remain as \( y = 2r^2 \) and \( y = 80 - 3r^2 \).

Thus, the integral becomes:
\[
V = \int_{\theta=0}^{2\pi} \int_{r=0}^{4} \int_{y = 2r^2}^{80 - 3r^2} r \, dy \, dr \, d\theta
\]

### Easiest Order of Integration
The cylindrical coordinate system simplifies the problem, making the integration order \( d\theta \, dr \, dy \) the easiest. Thus, check all that apply for this problem would include:

1. \( d\theta \, dr \, dy \) – preferred in cylindrical coordinates due to radial symmetry.

Would you like further details on each step or have any specific questions?

---

1. How do you derive the bounds for \( r \) and \( \theta \) in cylindrical coordinates?
2. What is the reason for choosing cylindrical coordinates here?
3. Can the integral be solved in Cartesian coordinates, and how complex would it be?
4. What are the limits for \( y \) in this integral, and how do they relate to the paraboloids?
5. How does the radial symmetry of the problem simplify the integration?

**Tip**: When dealing with circular or radial symmetry in 3D regions, cylindrical or spherical coordinates often simplify the setup and integration.

Express the volume of the solid enclosed by the paraboloids y=2x^2+2z^2 and y=80−3x^2−3z^2 with a triple integral. Given the region of integration, which would be the easiest order of integration? Check all that apply.

Learn how to find the volume of a solid enclosed by the paraboloids y=2x^2+2z^2 and y=80−3x^2−3z^2 with a triple integral. This solution includes finding the region's bounds, setting up the triple integral in cylindrical coordinates, and choosing the easiest order of integration for radial symmetry. Ideal for college-level calculus students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation