Find the volume of a right circular cone that had a height of 14.7 feet and a base with a radius of 2 feet. Round your answer to the nearest tenth of a cubic foot.

The volume \( V \) of a right circular cone is given by the formula:

\[
V = \frac{1}{3} \pi r^2 h
\]

where:
- \( r \) is the radius of the base
- \( h \) is the height of the cone

Plugging in the given values \( r = 2 \) feet and \( h = 14.7 \) feet:

\[
V = \frac{1}{3} \pi (2)^2 (14.7)
\]

\[
V = \frac{1}{3} \pi \cdot 4 \cdot 14.7
\]

\[
V = \frac{1}{3} \pi \cdot 58.8
\]

\[
V = 19.6 \pi
\]

Using \( \pi \approx 3.14159 \):

\[
V \approx 19.6 \times 3.14159 \approx 61.6
\]

Therefore, the volume of the cone is approximately 61.6 cubic feet.

Would you like more details, or do you have any questions?

Here are 5 related questions to explore further:
1. How would the volume change if the radius were doubled?
2. What is the formula for the surface area of a cone?
3. How do changes in the height affect the volume of the cone?
4. Can you find the volume of a truncated cone with given dimensions?
5. How is the volume formula for a cone derived?

**Tip:** Always check if the units are consistent before performing calculations.

Calculate the volume of a right circular cone with a height of 14.7 feet and a base radius of 2 feet. This detailed solution uses the cone volume formula V = (1/3)πr²h and rounds the result to the nearest tenth. Suitable for high school students in Grades 9-12.

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