Math Problem Statement

What is the volume of a cube whose surface area is 294? (A) 125 (B) 216 C) 294 (D) 343 4. The ratio of boys to girls in a certain classroom was 2 : 3. If boys represented five more than one-third of the class, how many people were in the classroom? (A) 30 (C) 75 5. What is the average of 530, 560, 517, 513 and 590? (A) 5210 (C) 529 +559 +516 +512 +589 6. Ifp+1<3p+5,then: (A) p<-2 (C) p=0 (B) 45 (D) 60 (B) 5209 (D) 5205 (B) p>-2 (D) p>2 7. If an equilateral triangle and a square have the same perimeter, what is the ratio of the lengths of the sides of the equilateral triangle to the lengths of the sides of the square? (A) 3 : 4 (C) 1 : 2 (B) 4 : 3 (D) 1 : 3

Solution

Let's go through these questions one by one.

1. Volume of a Cube with Surface Area 294

The surface area of a cube is given by the formula:

Surface Area=6s2\text{Surface Area} = 6s^2

where ss is the side length of the cube. To find the side length, we solve:

6s2=294s2=2946=49s=49=76s^2 = 294 \quad \Rightarrow \quad s^2 = \frac{294}{6} = 49 \quad \Rightarrow \quad s = \sqrt{49} = 7

Now, the volume VV of the cube is:

V=s3=73=343V = s^3 = 7^3 = 343

So, the correct answer is (D) 343.


2. Ratio of Boys to Girls in the Classroom

Let the total number of people in the class be xx. The ratio of boys to girls is 2:32:3, meaning the boys represent 25\frac{2}{5} of the total class, and girls represent 35\frac{3}{5} of the total class. According to the problem, boys are 5 more than one-third of the class. We set up the equation:

25x=13x+5\frac{2}{5}x = \frac{1}{3}x + 5

Multiply through by 15 to eliminate the fractions:

6x=5x+756x = 5x + 75

Solving for xx:

x=75x = 75

So, the total number of people in the class is (C) 75.


3. Average of 530, 560, 517, 513, and 590

The average is the sum of the numbers divided by the count of numbers. First, sum the values:

530+560+517+513+590=2710530 + 560 + 517 + 513 + 590 = 2710

Now, divide by the number of terms (5):

Average=27105=542\text{Average} = \frac{2710}{5} = 542

So, the average is 542, but this option doesn't seem listed. Let me know if there's a different set of choices to check!


4. Solve the inequality p+1<3p+5p + 1 < 3p + 5

First, subtract pp from both sides:

1<2p+51 < 2p + 5

Now subtract 5 from both sides:

4<2p-4 < 2p

Divide by 2:

p>2p > -2

So the correct answer is (B) p > -2.


5. Ratio of Side Lengths of an Equilateral Triangle and a Square

Let the side length of the equilateral triangle be striangles_{\text{triangle}} and the side length of the square be ssquares_{\text{square}}. The perimeter of an equilateral triangle is 3striangle3s_{\text{triangle}} and the perimeter of a square is 4ssquare4s_{\text{square}}. Since the perimeters are equal:

3striangle=4ssquare3s_{\text{triangle}} = 4s_{\text{square}}

Solving for the ratio:

strianglessquare=43\frac{s_{\text{triangle}}}{s_{\text{square}}} = \frac{4}{3}

So, the correct ratio is (B) 4:3.


Recap:

  1. (D) 343
  2. (C) 75
  3. Average: 542 (no matching option)
  4. (B) p > -2
  5. (B) 4:3

Do you want any further details or have questions on any part?

Relative Questions:

  1. How do you find the surface area of a rectangular prism?
  2. How does the ratio of girls to boys change if 5 more boys join the class?
  3. What is the median of a dataset, and how does it differ from the average?
  4. Can inequalities have more than one solution?
  5. How does the perimeter of a polygon affect its area?

Tip: When dealing with ratios, always simplify or cross-multiply to make comparisons easier.

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Math Problem Analysis

Mathematical Concepts

Geometry
Algebra
Averages
Ratios and Proportions
Inequalities

Formulas

Surface Area of a Cube: 6s^2
Volume of a Cube: s^3
Average: Sum of numbers / Number of terms
Ratio of Perimeters: 3s_triangle = 4s_square

Theorems

Properties of Equality and Inequality
Ratio and Proportion Theorems

Suitable Grade Level

Grades 6-8