Math Problem Statement

provide a step-by-step solution to the problem in the screenshot

Let a, b ∈ R³. Determine whether |a - b|² = |a|² + |b|² - 2(axbx + ayby + azbz).

Solution

We are asked to determine whether the identity holds:

ab2=a2+b22(axbx+ayby+azbz)|a - b|^2 = |a|^2 + |b|^2 - 2(a_x b_x + a_y b_y + a_z b_z) where a,bR3a, b \in \mathbb{R}^3.

Step 1: Recall the formula for the magnitude squared of a vector

For any vector v=(vx,vy,vz)R3v = (v_x, v_y, v_z) \in \mathbb{R}^3, its magnitude squared is given by:

v2=vx2+vy2+vz2|v|^2 = v_x^2 + v_y^2 + v_z^2

This means the magnitude squared of a vector is the sum of the squares of its components.

Step 2: Expand ab2|a - b|^2

The vector difference aba - b has components (axbx,ayby,azbz)(a_x - b_x, a_y - b_y, a_z - b_z), so we can write:

ab2=(axbx)2+(ayby)2+(azbz)2|a - b|^2 = (a_x - b_x)^2 + (a_y - b_y)^2 + (a_z - b_z)^2

Now expand each square:

(axbx)2=ax22axbx+bx2(a_x - b_x)^2 = a_x^2 - 2a_x b_x + b_x^2 (ayby)2=ay22ayby+by2(a_y - b_y)^2 = a_y^2 - 2a_y b_y + b_y^2 (azbz)2=az22azbz+bz2(a_z - b_z)^2 = a_z^2 - 2a_z b_z + b_z^2

Thus, we have:

ab2=(ax2+ay2+az2)+(bx2+by2+bz2)2(axbx+ayby+azbz)|a - b|^2 = (a_x^2 + a_y^2 + a_z^2) + (b_x^2 + b_y^2 + b_z^2) - 2(a_x b_x + a_y b_y + a_z b_z)

Step 3: Interpret the terms

Notice that:

  • ax2+ay2+az2=a2a_x^2 + a_y^2 + a_z^2 = |a|^2, which is the magnitude squared of vector aa,
  • bx2+by2+bz2=b2b_x^2 + b_y^2 + b_z^2 = |b|^2, which is the magnitude squared of vector bb,
  • axbx+ayby+azbz=aba_x b_x + a_y b_y + a_z b_z = a \cdot b, which is the dot product of vectors aa and bb.

Thus, the expanded form becomes:

ab2=a2+b22(ab)|a - b|^2 = |a|^2 + |b|^2 - 2(a \cdot b)

Step 4: Compare with the given expression

The given expression in the problem is:

ab2=a2+b22(axbx+ayby+azbz)|a - b|^2 = |a|^2 + |b|^2 - 2(a_x b_x + a_y b_y + a_z b_z)

This matches exactly with the expanded form of ab2|a - b|^2, since axbx+ayby+azbza_x b_x + a_y b_y + a_z b_z is the dot product aba \cdot b.

Conclusion:

The identity holds true. Therefore, the expression given in the problem is correct.


Would you like to explore more details or have any questions on this? Here are 5 related questions to deepen understanding:

  1. What is the geometric interpretation of the dot product aba \cdot b?
  2. How does the magnitude squared of ab|a - b| relate to the distance between the vectors aa and bb?
  3. Can this result be generalized to Rn\mathbb{R}^n (for vectors in nn-dimensional space)?
  4. How would the result change if we considered vectors in C3\mathbb{C}^3 (complex space)?
  5. What is the physical meaning of the magnitude and dot product in physics, particularly in mechanics?

Tip: Always break down vectors component-wise when working with their magnitudes and dot products—it helps simplify complex expressions.

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Math Problem Analysis

Mathematical Concepts

Vector Algebra
Dot Product
Euclidean Space

Formulas

|v|² = vₓ² + vᵧ² + v_z²
|a - b|² = |a|² + |b|² - 2(a · b)

Theorems

Properties of the Dot Product
Pythagorean Theorem in Vector Form

Suitable Grade Level

Grades 11-12 / College Level