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The question asks if the ordered pair \( \left( 0, \frac{1}{8} \right) \) is a solution to the equation:

\[
5a + 8b = 1
\]

We can solve this by substituting \( a = 0 \) and \( b = \frac{1}{8} \) into the equation.

\[
5(0) + 8\left(\frac{1}{8}\right) = 1
\]

Simplifying this:

\[
0 + 1 = 1
\]

This is true, so the ordered pair \( \left( 0, \frac{1}{8} \right) \) is indeed a solution to the equation.

Would you like further explanation on any part of this process?

Here are 5 related questions to deepen your understanding:

1. How would the solution change if the equation was \( 5a + 8b = 2 \)?
2. What is the general method to determine if an ordered pair is a solution to a linear equation?
3. Can a linear equation have more than one solution? If yes, how would you find them?
4. How does the slope of the line represented by \( 5a + 8b = 1 \) affect its graph?
5. What are the real-world applications of solving linear equations like this one?

**Tip:** When checking if an ordered pair is a solution to a given equation, always substitute the values of the pair into the equation and simplify to verify if the equation holds true.

Is the ordered pair (0, 1/8) a solution of the equation 5a + 8b = 1?

Learn how to verify if the ordered pair (0, 1/8) is a solution to the linear equation 5a + 8b = 1. This step-by-step guide demonstrates the substitution method, simplifying the equation to check the result. Suitable for students in Grades 8-10.

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