Math Problem Statement
Verify Euler’s theorem for the function u = f (x, y) = ax + 2hxy + by .
Solution
Euler’s theorem states that for a homogeneous function of degree , the following relation holds:
Here, we need to verify Euler's theorem for the function:
To do this, we will:
- Check if the function is homogeneous: A function is homogeneous if there exists a degree such that scaling all variables by a factor results in scaling the function by . This means:
-
Compute the partial derivatives and .
-
Apply Euler’s theorem by checking if holds.
Step 1: Check if is homogeneous
Let's scale and by , i.e., substitute and into :
= \lambda a x + 2h \lambda^2 xy + \lambda b y$$ Factoring out $$\lambda$$: $$u(\lambda x, \lambda y) = \lambda(ax + by) + \lambda^2(2hxy)$$ We can see that $$u(\lambda x, \lambda y)$$ is not proportional to a single power of $$\lambda$$, so it is **not homogeneous**. This means that Euler’s theorem, which applies to homogeneous functions, does **not apply** to this function. --- Since the function is not homogeneous, Euler's theorem is not valid for this function, and the verification stops here. Would you like more details or clarification on any part? --- Here are 5 follow-up questions related to this concept: 1. How can you identify the degree of a homogeneous function? 2. What happens if a function is homogeneous of degree zero? 3. Can Euler's theorem be applied to functions with mixed degree terms? 4. How does the scaling factor influence homogeneous functions? 5. Can a non-homogeneous function become homogeneous under a different transformation? **Tip**: Homogeneous functions play a key role in fields like economics, physics, and differential equations where scaling properties are important.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Homogeneous Functions
Partial Derivatives
Euler's Theorem
Formulas
x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y} = nu
u(x, y) = ax + 2hxy + by
Theorems
Euler's Theorem for Homogeneous Functions
Suitable Grade Level
College Level
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